In C#, you can use the Environment.NewLine property to get the appropriate newline character(s) for the current environment. By default, this will return a CRLF (\r\n) sequence, which represents a carriage return followed by a line feed.
To insert a line feed (LF) character instead of a CRLF sequence, you can simply replace Environment.NewLine with the LF character (\n).
Here's an example of how to insert a line feed character instead of a CRLF sequence when building a string in C#:
string myString = "This is a line of text." + "\n" + "This is another line of text.";
In this example, we're concatenating two strings with a LF character between them. The resulting string will have a line feed character between the two lines of text, instead of a CRLF sequence.
If you need to insert a line feed character in the middle of a string that already contains CRLF sequences, you can use the Replace() method to replace all occurrences of CRLF with LF:
string myStringWithCRLF = "This is a line of text.\r\nThis is another line of text."; string myStringWithLF = myStringWithCRLF.Replace("\r\n", "\n"); In this example, we're replacing all occurrences of CRLF with LF in the myStringWithCRLF string, resulting in the myStringWithLF string that contains only LF characters.
Insert LineFeed instead of CRLF in C#
string text = "Sample\r\ntext\r\nwith\r\nCRLF"; string replacedText = text.Replace("\r\n", "\n"); C# replace Carriage Return with Line Feed
string text = "Sample\rtext\rwith\rCRLF"; string replacedText = text.Replace("\r", "\n"); C# string manipulation Line Feed instead of CRLF
string text = "Sample\r\ntext\r\nwith\r\nCRLF"; string replacedText = text.Replace("\r\n", "\n").Replace("\r", "\n"); Replace CRLF with LF in C# string
string text = "Sample\r\ntext\r\nwith\r\nCRLF"; string replacedText = text.Replace("\r\n", "\n"); C# remove Carriage Return from string
string text = "Sample\rtext\rwith\rCRLF"; string replacedText = text.Replace("\r", ""); C# regex replace CRLF with LF
using System.Text.RegularExpressions; string text = "Sample\r\ntext\r\nwith\r\nCRLF"; string replacedText = Regex.Replace(text, "\r\n", "\n");
C# replace CRLF with LF using StringBuilder
using System.Text; StringBuilder sb = new StringBuilder("Sample\r\ntext\r\nwith\r\nCRLF"); sb.Replace("\r\n", "\n"); string replacedText = sb.ToString(); C# replace newline characters with LF
string text = "Sample\r\ntext\r\nwith\r\nCRLF"; string replacedText = text.Replace("\r\n", "\n").Replace("\n", "\n"); C# remove Carriage Return from multiline string
string text = "Sample\r\ntext\r\nwith\r\nCRLF"; string[] lines = text.Split('\n'); string replacedText = string.Join("\n", lines); Convert CRLF to LF in C#
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