Create 1507_Reformat_Date.md

Author: koji

1507_Reformat_Date.md

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+## 1507. Reformat Date
+
+```
+Given a date string in the form Day Month Year, where:
+
+Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
+Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
+Year is in the range [1900, 2100].
+Convert the date string to the format YYYY-MM-DD, where:
+
+YYYY denotes the 4 digit year.
+MM denotes the 2 digit month.
+DD denotes the 2 digit day.
+ 
+
+Example 1:
+
+Input: date = "20th Oct 2052"
+Output: "2052-10-20"
+Example 2:
+
+Input: date = "6th Jun 1933"
+Output: "1933-06-06"
+Example 3:
+
+Input: date = "26th May 1960"
+Output: "1960-05-26"
+ 
+
+Constraints:
+
+The given dates are guaranteed to be valid, so no error handling is necessary.
+```
+
+
+```python
+class Solution:
+ def reformatDate(self, date: str) -> str:
+ m_dic = {"Jan":'01', "Feb":'02', "Mar":'03', "Apr":'04', "May":'05', "Jun":'06', "Jul":'07', "Aug":'08', "Sep":'09', "Oct":'10', "Nov":'11', "Dec":'12'}
+ 
+ date_str = date.split()
+ y = str(date_str[2])
+ m = str(m_dic[date_str[1]])
+ d = str(date_str[0][:-2])
+ if len(d) == 1:
+ d = '0' + d
+ # print(y + '-' + m + '-' + d)
+ return '{}-{}-{}'.format(y, m, d)
+```
+
+
+
+```
+Runtime: 52 ms, faster than 6.19% of Python3 online submissions for Reformat Date.
+Memory Usage: 14.4 MB, less than 19.79% of Python3 online submissions for Reformat Date.
+```