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| 1 | +## Amazon | OA | Rover Control |
| 2 | + |
| 3 | +Amazon Online Assessment: https://leetcode.com/discuss/interview-question/985703/Amazon-or-OA-or-Rover-Control |
| 4 | + |
| 5 | + A Mars rover is directed to move within a square matrix. It accepts a sequence of |
| 6 | + commands to move in any of the four directions from each cell: [UP, DOWN, LEFT or |
| 7 | + RIGHT]. The rover starts from cell 0. and may not move diagonally or outside of |
| 8 | + the boundary. |
| 9 | + |
| 10 | + Each cell in the matrix has a position equal to: |
| 11 | + (row * size) + column |
| 12 | + where row and column are zero-indexed, size = row length of the matrix. |
| 13 | + |
| 14 | + Return the final position of the rover after all moves. |
| 15 | + |
| 16 | + Example |
| 17 | + n = 4 |
| 18 | + commands = [RIGHT, UP, DOWN, LEFT, DOWN, DOWN] |
| 19 | + |
| 20 | + The rover path is shown below. |
| 21 | + |
| 22 | + 0 1 2 3 |
| 23 | + 4 5 6 7 |
| 24 | + 8 9 10 11 |
| 25 | + 12 13 14 15 |
| 26 | + |
| 27 | + RIGHT: Rover moves to position 1 |
| 28 | + UP: Position unchanged, as the move would take the rover out of the boundary. |
| 29 | + DOWN: Rover moves to Position 5. |
| 30 | + LEFT: Rover moves to position 4 |
| 31 | + DOWN: Rover moves to position 8 |
| 32 | + DOWN: The rover ends up in position 12. |
| 33 | + |
| 34 | + The function returns 12. |
| 35 | + |
| 36 | + Function Description |
| 37 | + Complete the function roverMove in the editor below. |
| 38 | + roverMove has the following parameter(s): |
| 39 | + int n: the size of the square matrix |
| 40 | + string cmds[m]: the commands |
| 41 | + |
| 42 | + Returns |
| 43 | + int: the label of the cell the rover occupies after executing all commands |
| 44 | + |
| 45 | + Constraints |
| 46 | + 2 <= n <= 20 |
| 47 | + 1 <= |cmds| <= 20 |
| 48 | + |
| 49 | + Input Format For Custom Testing |
| 50 | + |
| 51 | + Input from stdin will be processed as follows and passed to the function. |
| 52 | + The first line contains an integer, n, denoting the size of the square matrix. |
| 53 | + The next line contains an integer, m, the number of commands to follow. |
| 54 | + Each of the next m lines contains a command string, cmds[i]. |
| 55 | + |
| 56 | + Sample Input : |
| 57 | + STDIN Function |
| 58 | + |
| 59 | + 4 → n = 4 |
| 60 | + 5 → cmds [] size m = 5 |
| 61 | + RIGHT → cmds = ['RIGHT', 'DOWN', 'LEFT', 'LEFT', 'DOWN'] |
| 62 | + DOWN |
| 63 | + LEFT |
| 64 | + LEFT |
| 65 | + DOWN |
| 66 | + |
| 67 | + Sample Output: |
| 68 | + 8 |
| 69 | + |
| 70 | + Explanation: |
| 71 | + 0 1 2 3 |
| 72 | + 4 5 6 7 |
| 73 | + 8 9 10 11 |
| 74 | + 12 13 14 15 |
| 75 | + Rover starts at position 0 |
| 76 | + RIGHT → pos 1 |
| 77 | + DN → pos 5 |
| 78 | + LEFT → pos 4 |
| 79 | + LEFT → pos 4, No effect |
| 80 | + DOWN → pos 8 |
| 81 | + ''' |
| 82 | + |
| 83 | + |
| 84 | +```python |
| 85 | +def rover(n, cmds): |
| 86 | + pos = 0 |
| 87 | + for c in cmds: |
| 88 | + if c == 'UP': |
| 89 | + if pos//n >=1: |
| 90 | + pos -= n |
| 91 | + elif c == 'DOWN': |
| 92 | + if pos//n < n-1: |
| 93 | + pos += n |
| 94 | + elif c == 'RIGHT': |
| 95 | + if (pos % n) < n-1: |
| 96 | + pos +=1 |
| 97 | + elif c == 'LEFT': |
| 98 | + if (pos % n) >=1: |
| 99 | + pos -= 1 |
| 100 | + return pos |
| 101 | + |
| 102 | +n = 4 |
| 103 | +cmds = ['RIGHT', 'DOWN', 'LEFT', 'LEFT', 'DOWN'] # 8 |
| 104 | +cmds2 = ['RIGHT', 'UP', 'DOWN', 'LEFT', 'DOWN', 'DOWN'] # 12 |
| 105 | +expected_output2 = 8 |
| 106 | +expected_output2 = 12 |
| 107 | +output = rover(n, cmds) |
| 108 | +output2 = rover(n, cmds2) |
| 109 | +print(output) |
| 110 | +print(output == expected_output) |
| 111 | +print(output2) |
| 112 | +print(output2 == expected_output2) |
| 113 | +``` |
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