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Python program to Search an Element in a Circular Linked List

Last Updated : 18 May, 2022
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A linked list is a kind of linear data structure where each node has a data part and an address part which points to the next node. A circular linked list is a type of linked list where the last node points to the first one, making a circle of nodes.

Example:

Input: CList = 6->5->4->3->2, find = 3 Output: Element is present Input: CList = 6->5->4->3->2, find = 1 Output: Element is not present

Search an Element in a Circular Linked List

For example, if the key to be searched is 30 and the linked list is 5->4->3->2, then the function should return false. If the key to be searched is 4, then the function should return true. 

Approach: 

  1. Initialize a node pointer, temp = head.
  2. Initialize a counter f=0 (to check if the element is present in a linked list or not).
  3. If the head is null then the print list is empty.
  4. Else start traversing the Linked List and if element found in Linked List increment in f.
  5. If the counter is zero, then the print element is not found.
  6. Else print element is present.

Below is the implementation of the above approach:

Python3
# Python program to Search an Element # in a Circular Linked List # Class to define node of the linked list  class Node: def __init__(self,data): self.data = data; self.next = None; class CircularLinkedList: # Declaring Circular Linked List def __init__(self): self.head = Node(None); self.tail = Node(None); self.head.next = self.tail; self.tail.next = self.head; # Adds new nodes to the Circular Linked List def add(self,data): # Declares a new node to be added newNode = Node(data); # Checks if the Circular # Linked List is empty if self.head.data is None: # If list is empty then new node # will be the first node # to be added in the Circular Linked List self.head = newNode; self.tail = newNode; newNode.next = self.head; else: # If a node is already present then # tail of the last node will point to # new node self.tail.next = newNode; # New node will become new tail self.tail = newNode; # New Tail will point to the head self.tail.next = self.head; # Function to search the element in the  # Circular Linked List def findNode(self,element): # Pointing the head to start the search current = self.head; i = 1; # Declaring f = 0 f = 0; # Check if the list is empty or not  if(self.head == None): print("Empty list"); else: while(True): # Comparing the elements # of each node to the # element to be searched if(current.data == element): # If the element is present # then incrementing f f += 1; break; # Jumping to next node current = current.next; i = i + 1; # If we reach the head # again then element is not  # present in the list so  # we will break the loop if(current == self.head): break; # Checking the value of f if(f > 0): print("element is present"); else: print("element is not present"); # Driver Code if __name__ == '__main__': # Creating a Circular Linked List  '''  Circular Linked List we will be working on:  1 -> 2 -> 3 -> 4 -> 5 -> 6  ''' circularLinkedList = CircularLinkedList(); #Adding nodes to the list  circularLinkedList.add(1); circularLinkedList.add(2); circularLinkedList.add(3); circularLinkedList.add(4); circularLinkedList.add(5); circularLinkedList.add(6); # Searching for node 2 in the list  circularLinkedList.findNode(2); #Searching for node in the list  circularLinkedList.findNode(7); 

Output:

element is present element is not present

Time Complexity: O(N), where N is the length of the Circular linked list.


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