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numpy.less() in Python

Last Updated : 08 Mar, 2024
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The numpy.less() : checks whether x1 is lesser than x2 or not. Syntax : 

numpy.less(x1, x2[, out])

Parameters : 

x1, x2 : [array_like]Input arrays. If x1.shape != x2.shape, they must be broadcastable to a common shape out : [ndarray, boolean]Array of bools, or a single bool if x1 and x2 are scalars.

Return : 

Boolean array indicating results, whether x1 is lesser than x2 or not.

Code 1 : 

Python 
# Python Program illustrating # numpy.less() method import numpy as geek a = geek.less([8., 2.], [5., 3.]) print("Not equal : \n", a, "\n") b = geek.less([2, 2], [[1, 3],[1, 4]]) print("Not equal : \n", b, "\n") a = geek.array([4,2]) b = geek.array([6,2]) print("Is a lesser than b : ", a < b)

Output : 

Not equal : [False True] Not equal : [[False True] [False True]] Is a lesser than b : [ True False]]

Code 2 : 

Python 
# Python Program illustrating # numpy.less() method import numpy as geek # Here we will compare Complex values with int  a = geek.array([1j,2]) b = geek.array([1,2]) # indicating 1j is lesser than 1 print("Comparing complex with int : ", a < b) # indicating 1j is lesser than 1 d = geek.less(a, b) print("\n Comparing complex with int .less() : ", d)

Output : 

Comparing complex with int : [ True False] Comparing complex with int .less() : [ True False]

Code 3 : 

Python 
# Python Program illustrating # numpy.less() method import numpy as geek # Here we will compare Float with int values a = geek.array([1.1, 1]) b = geek.array([1, 2]) # indicating 1.1 is greater than 1 print("Comparing float with int : ", a < b) # indicating 1.1 is greater than 1 d = geek.less(a, b) print("\n Comparing float with int using .less() : ", d)

Output : 

Comparing float with int : [False True] Comparing float with int using .less() : [False True]

Next Article
numpy.find() in Python

M

Mohit Gupta

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