JavaScript Program to find Lexicographically next String

In this article, we are going to learn how can we find the Lexicographically next string. Lexicographically next string refers to finding the string that follows a given string in a dictionary or alphabetical order.

Examples:

Input : test
Output : tesu
Explanation : The last character 't' is changed to 'u'.
Input : xyz
Output : xzz
Explanation : Since we can't increase last character, 
we increment previous character.
Input : z
Output : za
Explanation : If string is empty, we return ‘a’. If string contains all characters as ‘z’, we append ‘a’ at the end.
Otherwise we find first character from end which is not z and increment it.

Approach

• If the input string s is empty, it returns "a" as the next word.
• It finds the rightmost character in the string that is not 'z'.
• If all characters in the string are 'z', it appends 'a' at the end.
• If there are non-'z' characters in the string, it increments the rightmost non-'z' character by one.

Example: This example shows the implementation of the above mentioned approach.

function nextWord(s) {  // If string is empty.  if (s == "")  return "a";  // Find first character from right  // which is not z.  let i = s.length - 1;  while (s[i] == 'z' && i >= 0)  i--;  // If all characters are 'z', append  // an 'a' at the end.  if (i == -1)  s = s + 'a';  // If there are some non-z characters  else  s[i] = String.fromCharCode(s[i]  .charCodeAt(0) + 1);  return s.join(''); } // Driver code let str = "abcd".split(''); console.log(nextWord(str)); 

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Time Complexity: O(n)

Auxiliary Space: O(1)

String Manipulation Without Conversion

Idea: Process the string from the end to the start, and handle cases where characters are 'z' by incrementing and managing the carry over.

Steps:

1. Process the String from End to Start: Traverse the string from the rightmost character to the leftmost.
2. Handle 'z' Characters: If a 'z' is found, change it to 'a' and move to the next character to the left.
3. Increment Non-'z' Characters: Once a non-'z' character is found, increment it by one and terminate further processing.
4. Append 'a' if All Characters are 'z': If the string consists entirely of 'z's, append an 'a' at the end.

Example:

function nextWord(s) {  let str = s;  let arr = [...str];  let n = arr.length;  // Start from the end of the string  for (let i = n - 1; i >= 0; i--) {  if (arr[i] === 'z') {  // Change 'z' to 'a'  arr[i] = 'a';  } else {  // Increment the character and exit  arr[i] = String.fromCharCode(arr[i].charCodeAt(0) + 1);  return arr.join('');  }  }  return 'a' + arr.join(''); } let str = "abcz"; console.log(nextWord(str));  

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