Divide large number represented as string Last Updated : 29 Apr, 2024 Summarize Suggest changes Share Like Article Like Report Given a large number (represented as a string) which has to divide by another number (represented as int data type). The large number can be very large which does not even fit in long long in C++. The task is to find the division of these numbers. Examples: Input : number = 1260257 divisor = 37Output : 34061(See below diagram)Input : number = 12313413534672234 divisor = 754Output : 16330787181262Input : number = 1248163264128256512 divisor = 125Output : 9985306113026052Recommended PracticeLarge number divisionTry It!We have already discussed Multiply Large Numbers represented as Strings.We use basic school mathematics as shown in below example. As the dividend and result can be very large we store them in string. We first take digits which are divisible by number. After this take each digit and store result in string. Implementation: C++ // C++ program to implement division with large // number #include <bits/stdc++.h> using namespace std; // A function to perform division of large numbers string longDivision(string number, int divisor) { // As result can be very large store it in string string ans; // Find prefix of number that is larger // than divisor. int idx = 0; int temp = number[idx] - '0'; while (idx < (number.size() - 1) && temp < divisor) temp = temp * 10 + (number[++idx] - '0'); // Repeatedly divide divisor with temp. After // every division, update temp to include one // more digit. while ((number.size() - 1) > idx) { // Store result in answer i.e. temp / divisor ans += (temp / divisor) + '0'; // Take next digit of number temp = (temp % divisor) * 10 + number[++idx] - '0'; } ans += (temp / divisor) + '0'; // If divisor is greater than number if (ans.length() == 0) return "0"; // else return ans return ans; } // Driver program to test longDivision() int main() { string number = "1248163264128256512"; int divisor = 125; cout << longDivision(number, divisor); return 0; } Java // Java program to implement division // with large number import java.io.*; public class GFG { public static String longDivision( String number, int divisor) { // As result can be very // large store it in string // but since we need to modify // it very often so using // string builder StringBuilder result = new StringBuilder(); // We will be iterating // the dividend so converting // it to char array char[] dividend = number.toCharArray(); // Initially the carry // would be zero int carry = 0; // Iterate the dividend for ( int i = 0; i < dividend.length; i++) { // Prepare the number to // be divided int x = carry * 10 + Character.getNumericValue( dividend[i]); // Append the result with // partial quotient result.append(x / divisor); // Prepare the carry for // the next Iteration carry = x % divisor; } // Remove any leading zeros for ( int i = 0; i < result.length(); i++) { if ( result.charAt(i) != '0') { // Return the result return result.substring(i); } } // Return empty string // if number is empty return ""; } // Driver code public static void main( String[] args) { String number = "1248163264128256512"; int divisor = 125; System.out.println( longDivision( number, divisor)); } } // This code is contributed by Saurabh321Gupta. Python3 # Python3 program to implement division # with large number import math # A function to perform division of # large numbers def longDivision(number, divisor): # As result can be very large # store it in string ans = ""; # Find prefix of number that # is larger than divisor. idx = 0; temp = ord(number[idx]) - ord('0'); while (temp < divisor): temp = (temp * 10 + ord(number[idx + 1]) - ord('0')); idx += 1; idx += 1; # Repeatedly divide divisor with temp. # After every division, update temp to # include one more digit. while ((len(number)) > idx): # Store result in answer i.e. temp / divisor ans += chr(math.floor(temp // divisor) + ord('0')); # Take next digit of number temp = ((temp % divisor) * 10 + ord(number[idx]) - ord('0')); idx += 1; ans += chr(math.floor(temp // divisor) + ord('0')); # If divisor is greater than number if (len(ans) == 0): return "0"; # else return ans return ans; # Driver Code number = "1248163264128256512"; divisor = 125; print(longDivision(number, divisor)); # This code is contributed by mits C# // C# program to implement division // with large number using System; class GFG { // A function to perform division of large numbers static string longDivision(string number, int divisor) { // As result can be very large store it in string string ans = ""; // Find prefix of number that is larger // than divisor. int idx = 0; int temp = (int)(number[idx] - '0'); while (temp < divisor) { temp = temp * 10 + (int)(number[idx + 1] - '0'); idx++; } ++idx; // Repeatedly divide divisor with temp. After // every division, update temp to include one // more digit. while (number.Length > idx) { // Store result in answer i.e. temp / divisor ans += (char)(temp / divisor + '0'); // Take next digit of number temp = (temp % divisor) * 10 + (int)(number[idx] - '0'); idx++; } ans += (char)(temp / divisor + '0'); // If divisor is greater than number if (ans.Length == 0) return "0"; // else return ans return ans; } // Driver code static void Main() { string number = "1248163264128256512"; int divisor = 125; Console.WriteLine(longDivision(number, divisor)); } } // This code is contributed by mits JavaScript // Javascript program to implement division // with large number function longDivision(number,divisor) { // As result can be very // large store it in string // but since we need to modify // it very often so using // string builder let ans=""; // We will be iterating // the dividend so converting // it to char array // Initially the carry // would be zero let idx = 0; let temp=number[idx]-'0'; while (temp < divisor) { temp = (temp * 10 + (number[idx + 1]).charCodeAt(0) - ('0').charCodeAt(0)); idx += 1; } idx += 1; while(number.length>idx) { // Store result in answer i.e. temp / divisor ans += String.fromCharCode (Math.floor(temp / divisor) + ('0').charCodeAt(0)); // Take next digit of number temp = ((temp % divisor) * 10 + (number[idx]).charCodeAt(0) - ('0').charCodeAt(0)); idx += 1; } ans += String.fromCharCode (Math.floor(temp / divisor) + ('0').charCodeAt(0)); //If divisor is greater than number if(ans.length==0) return "0"; //else return ans return ans; } // Driver Code let number = "1248163264128256512"; let divisor = 125; console.log(longDivision( number, divisor)); // This code is contributed // by avanitrachhadiya2155 PHP <?php // PHP program to implement division // with large number // A function to perform division of // large numbers function longDivision($number, $divisor) { // As result can be very large // store it in string $ans = ""; // Find prefix of number that is // larger than divisor. $idx = 0; $temp = ord($number[$idx]) - 48; while ($temp < $divisor) $temp = $temp * 10 + ord($number[++$idx]) - 48; // Repeatedly divide divisor with temp. // After every division, update temp to // include one more digit. ++$idx; while (strlen($number) > $idx) { // Store result in answer i.e. temp / divisor $ans .= chr((int)($temp / $divisor) + 48); // Take next digit of number $temp = ($temp % $divisor) * 10 + ord($number[$idx]) - 48; ++$idx; } $ans .= chr((int)($temp / $divisor) + 48); // If divisor is greater than number if (strlen($ans) == 0) return "0"; // else return ans return $ans; } // Driver Code $number = "1248163264128256512"; $divisor = 125; print(longDivision($number, $divisor)); // This code is contributed by mits ?> Output9985306113026052Time Complexity: O(n2!), where n denoting length of string.Auxiliary Space: O(n). Advertise with us Next Article Subsequence and Substring A Aayush Rawat Similar Reads String in Data Structure A string is a sequence of characters. The following facts make string an interesting data structure.Small set of elements. Unlike normal array, strings typically have smaller set of items. For example, lowercase English alphabet has only 26 characters. ASCII has only 256 characters.Strings are immut 2 min read Introduction to Strings - Data Structure and Algorithm Tutorials Strings are sequences of characters. The differences between a character array and a string are, a string is terminated with a special character ‘\0’ and strings are typically immutable in most of the programming languages like Java, Python and JavaScript. Below are some examples of strings:"geeks" 7 min read Applications, Advantages and Disadvantages of String The String data structure is the backbone of programming languages and the building blocks of communication. 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Strings as character arrays C char str[4] = "GfG"; /*One extra for string terminator*/ /* OR */ char str[4] = {‘G’, ‘f’, ‘G’, '\0'}; /* '\0' is string terminator */ When strings are declared as character arra 5 min read Strings in different languageStrings in CA String in C programming is a sequence of characters terminated with a null character '\0'. The C String is work as an array of characters. The difference between a character array and a C string is that the string in C is terminated with a unique character '\0'.DeclarationDeclaring a string in C i 5 min read std::string class in C++C++ has in its definition a way to represent a sequence of characters as an object of the class. This class is called std:: string. The string class stores the characters as a sequence of bytes with the functionality of allowing access to the single-byte character.String vs Character ArrayStringChar 8 min read String Class in JavaA string is a sequence of characters. 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We need to write a program to print the characters of this string in sorted order.Examples: Input : "dcab" Output : "abcd"Input : "geeksforgeeks"Output : "eeeefggkkorss"Naive Approach - O(n Log n) TimeA simple approach is to use sorting algorith 5 min read Frequency of Characters in Alphabetical OrderGiven a string s, the task is to print the frequency of each of the characters of s in alphabetical order.Example: Input: s = "aabccccddd" Output: a2b1c4d3 Since it is already in alphabetical order, the frequency of the characters is returned for each character. Input: s = "geeksforgeeks" Output: e4 9 min read Swap characters in a StringGiven a String S of length N, two integers B and C, the task is to traverse characters starting from the beginning, swapping a character with the character after C places from it, i.e. swap characters at position i and (i + C)%N. Repeat this process B times, advancing one position at a time. Your ta 14 min read C Program to Find the Length of a StringThe length of a string is the number of characters in it without including the null character (‘\0’). In this article, we will learn how to find the length of a string in C.The easiest way to find the string length is by using strlen() function from the C strings library. Let's take a look at an exa 2 min read How to insert characters in a string at a certain position?Given a string str and an array of indices chars[] that describes the indices in the original string where the characters will be added. For this post, let the character to be inserted in star (*). Each star should be inserted before the character at the given index. Return the modified string after 7 min read Check if two strings are same or notGiven two strings, the task is to check if these two strings are identical(same) or not. Consider case sensitivity.Examples:Input: s1 = "abc", s2 = "abc" Output: Yes Input: s1 = "", s2 = "" Output: Yes Input: s1 = "GeeksforGeeks", s2 = "Geeks" Output: No Approach - By Using (==) in C++/Python/C#, eq 7 min read Concatenating Two Strings in CConcatenating two strings means appending one string at the end of another string. In this article, we will learn how to concatenate two strings in C.The most straightforward method to concatenate two strings is by using strcat() function. Let's take a look at an example:C#include <stdio.h> #i 2 min read Remove all occurrences of a character in a stringGiven a string and a character, remove all the occurrences of the character in the string.Examples: Input : s = "geeksforgeeks" c = 'e'Output : s = "gksforgks"Input : s = "geeksforgeeks" c = 'g'Output : s = "eeksforeeks"Input : s = "geeksforgeeks" c = 'k'Output : s = "geesforgees"Using Built-In Meth 2 min read Binary StringCheck if all bits can be made same by single flipGiven a binary string, find if it is possible to make all its digits equal (either all 0's or all 1's) by flipping exactly one bit. Input: 101Output: YeExplanation: In 101, the 0 can be flipped to make it all 1Input: 11Output: NoExplanation: No matter whichever digit you flip, you will not get the d 5 min read Number of flips to make binary string alternate | Set 1Given a binary string, that is it contains only 0s and 1s. We need to make this string a sequence of alternate characters by flipping some of the bits, our goal is to minimize the number of bits to be flipped. Examples : Input : str = “001†Output : 1 Minimum number of flips required = 1 We can flip 8 min read Binary representation of next numberGiven a binary string that represents binary representation of positive number n, the task is to find the binary representation of n+1. The binary input may or may not fit in an integer, so we need to return a string.Examples: Input: s = "10011"Output: "10100"Explanation: Here n = (19)10 = (10011)2n 6 min read Min flips of continuous characters to make all characters same in a stringGiven a string consisting only of 1's and 0's. In one flip we can change any continuous sequence of this string. Find this minimum number of flips so the string consist of same characters only.Examples: Input : 00011110001110Output : 2We need to convert 1's sequenceso string consist of all 0's.Input 8 min read Generate all binary strings without consecutive 1'sGiven an integer n, the task is to generate all binary strings of size n without consecutive 1's.Examples: Input : n = 4Output : 0000 0001 0010 0100 0101 1000 1001 1010Input : n = 3Output : 000 001 010 100 101Approach:The idea is to generate all binary strings of length n without consecutive 1's usi 6 min read K'th bit in a binary representation with n iterationsGiven a decimal number m. Consider its binary representation string and apply n iterations. In each iteration, replace the character 0 with the string 01, and 1 with 10. Find the kth (1-based indexing) character in the string after the nth iterationExamples: Input: m = 5, n = 2, k = 5Output: 0Explan 15+ min read Substring and SubsequenceAll substrings of a given StringGiven a string s, containing lowercase alphabetical characters. The task is to print all non-empty substrings of the given string.Examples : Input : s = "abc"Output : "a", "ab", "abc", "b", "bc", "c"Input : s = "ab"Output : "a", "ab", "b"Input : s = "a"Output : "a"[Expected Approach] - Using Iterati 8 min read Print all subsequences of a stringGiven a string, we have to find out all its subsequences of it. A String is said to be a subsequence of another String, if it can be obtained by deleting 0 or more character without changing its order.Examples: Input : abOutput : "", "a", "b", "ab"Input : abcOutput : "", "a", "b", "c", "ab", "ac", " 12 min read Count Distinct SubsequencesGiven a string str of length n, your task is to find the count of distinct subsequences of it.Examples: Input: str = "gfg"Output: 7Explanation: The seven distinct subsequences are "", "g", "f", "gf", "fg", "gg" and "gfg" Input: str = "ggg"Output: 4Explanation: The four distinct subsequences are "", 13 min read Count distinct occurrences as a subsequenceGiven two strings pat and txt, where pat is always shorter than txt, count the distinct occurrences of pat as a subsequence in txt.Examples: Input: txt = abba, pat = abaOutput: 2Explanation: pat appears in txt as below two subsequences.[abba], [abba]Input: txt = banana, pat = banOutput: 3Explanation 15+ min read Longest Common Subsequence (LCS)Given two strings, s1 and s2, the task is to find the length of the Longest Common Subsequence. If there is no common subsequence, return 0. A subsequence is a string generated from the original string by deleting 0 or more characters, without changing the relative order of the remaining characters. 15+ min read Shortest Superstring ProblemGiven a set of n strings arr[], find the smallest string that contains each string in the given set as substring. We may assume that no string in arr[] is substring of another string.Examples: Input: arr[] = {"geeks", "quiz", "for"}Output: geeksquizforExplanation: "geeksquizfor" contains all the thr 15+ min read Printing Shortest Common SupersequenceGiven two strings s1 and s2, find the shortest string which has both s1 and s2 as its sub-sequences. If multiple shortest super-sequence exists, print any one of them.Examples:Input: s1 = "geek", s2 = "eke"Output: geekeExplanation: String "geeke" has both string "geek" and "eke" as subsequences.Inpu 9 min read Shortest Common SupersequenceGiven two strings s1 and s2, the task is to find the length of the shortest string that has both s1 and s2 as subsequences.Examples: Input: s1 = "geek", s2 = "eke"Output: 5Explanation: String "geeke" has both string "geek" and "eke" as subsequences.Input: s1 = "AGGTAB", s2 = "GXTXAYB"Output: 9Explan 15+ min read Longest Repeating SubsequenceGiven a string s, the task is to find the length of the longest repeating subsequence, such that the two subsequences don't have the same string character at the same position, i.e. any ith character in the two subsequences shouldn't have the same index in the original string. Examples:Input: s= "ab 15+ min read Longest Palindromic Subsequence (LPS)Given a string s, find the length of the Longest Palindromic Subsequence in it. Note: The Longest Palindromic Subsequence (LPS) is the maximum-length subsequence of a given string that is also a Palindrome. Longest Palindromic SubsequenceExamples:Input: s = "bbabcbcab"Output: 7Explanation: Subsequen 15+ min read Longest Palindromic SubstringGiven a string s, the task is to find the longest substring which is a palindrome. If there are multiple answers, then return the first appearing substring.Examples:Input: s = "forgeeksskeegfor" Output: "geeksskeeg"Explanation: There are several possible palindromic substrings like "kssk", "ss", "ee 12 min read PalindromeC Program to Check for Palindrome StringA string is said to be palindrome if the reverse of the string is the same as the string. In this article, we will learn how to check whether the given string is palindrome or not using C program.The simplest method to check for palindrome string is to reverse the given string and store it in a temp 4 min read Check if a given string is a rotation of a palindromeGiven a string, check if it is a rotation of a palindrome. For example your function should return true for "aab" as it is a rotation of "aba". Examples: Input: str = "aaaad" Output: 1 // "aaaad" is a rotation of a palindrome "aadaa" Input: str = "abcd" Output: 0 // "abcd" is not a rotation of any p 15+ min read Check if characters of a given string can be rearranged to form a palindromeGiven a string, Check if the characters of the given string can be rearranged to form a palindrome. For example characters of "geeksogeeks" can be rearranged to form a palindrome "geeksoskeeg", but characters of "geeksforgeeks" cannot be rearranged to form a palindrome. Recommended PracticeAnagram P 14 min read Online algorithm for checking palindrome in a streamGiven a stream of characters (characters are received one by one), write a function that prints 'Yes' if a character makes the complete string palindrome, else prints 'No'. Examples:Input: str[] = "abcba"Output: a Yes // "a" is palindrome b No // "ab" is not palindrome c No // "abc" is not palindrom 15+ min read Print all Palindromic Partitions of a String using Bit ManipulationGiven a string, find all possible palindromic partitions of a given string. Note that this problem is different from Palindrome Partitioning Problem, there the task was to find the partitioning with minimum cuts in input string. Here we need to print all possible partitions. Example: Input: nitinOut 10 min read Minimum Characters to Add at Front for PalindromeGiven a string s, the task is to find the minimum number of characters to be added to the front of s to make it palindrome. A palindrome string is a sequence of characters that reads the same forward and backward. Examples: Input: s = "abc"Output: 2Explanation: We can make above string palindrome as 12 min read Make largest palindrome by changing at most K-digitsYou are given a string s consisting of digits (0-9) and an integer k. Convert the string into a palindrome by changing at most k digits. If multiple palindromes are possible, return the lexicographically largest one. If it's impossible to form a palindrome with k changes, return "Not Possible".Examp 14 min read Minimum Deletions to Make a String PalindromeGiven a string s of length n, the task is to remove or delete the minimum number of characters from the string so that the resultant string is a palindrome. Note: The order of characters should be maintained. Examples : Input : s = "aebcbda"Output : 2Explanation: Remove characters 'e' and 'd'. Resul 15+ min read Minimum insertions to form a palindrome with permutations allowedGiven a string of lowercase letters. Find minimum characters to be inserted in the string so that it can become palindrome. We can change the positions of characters in the string.Examples: Input: geeksforgeeksOutput: 2Explanation: geeksforgeeks can be changed as: geeksroforskeeg or geeksorfroskeeg 5 min read Article Tags : Strings Mathematical DSA Samsung large-numbers +1 More Practice Tags : SamsungMathematicalStrings Like