Check for Binary String

Given a string s, the task is to check if it is a binary string or not. A binary string is a string which only contains the characters '0' and '1'.

Examples:

Input: s = "01010101010"
Output: true

Input: s = "geeks101"
Output: false

Approach:

The idea is to iterate over all the characters of the string and if we encounter a character other than '0' or '1', then the input string is not a binary string. Otherwise, if all the characters are either '0' or '1', then the input string is a binary string.

// C++ Program to check if a string is // binary string or not #include <iostream> using namespace std; bool isBinary(string &s) {  for (int i = 0; i < s.length(); i++) {  // Check if the character is neither  // '0' nor '1'  if (s[i] != '0' && s[i] != '1') {  return false;  }  }  return true; } int main() {  string s = "01010101010";  cout << (isBinary(s) ? "true" : "false");  return 0; } 

// C Program to check if a string is  // binary string or not #include <stdio.h> #include <string.h> #include <stdbool.h> bool isBinary(char *s) {  for(int i = 0; i < strlen(s); i++) {    // Check if the character is neither   // '0' nor '1'  if(s[i] != '0' && s[i] != '1') {  return false;   }  }  return true;  } int main() {  char s[] = "01010101010";  printf(isBinary(s) ? "true" : "false");  return 0; } 

// Java Program to check if a string is  // binary string or not class GfG {  static boolean isBinary(String s) {  for (int i = 0; i < s.length(); i++) {    // Check if the character is neither   // '0' nor '1'  if (s.charAt(i) != '0' && s.charAt(i) != '1') {  return false;  }  }  return true;  }  public static void main(String[] args) {  String s = "01010101010";  System.out.println(isBinary(s));  } } 

# Python Program to check if a string is  # binary string or not def isBinary(s): for i in range(len(s)): # Check if the character is neither  # '0' nor '1' if s[i] != '0' and s[i] != '1': return False return True s = "01010101010" print("true" if isBinary(s) else "false") 

// C# Program to check if a string is  // binary string or not using System; class GfG {  static bool isBinary(string s) {  for (int i = 0; i < s.Length; i++) {    // Check if the character is neither   // '0' nor '1'  if (s[i] != '0' && s[i] != '1') {  return false;  }  }  return true;  }  static void Main() {  string s = "01010101010";  Console.WriteLine(isBinary(s) ? "true" : "false");  } } 

// JavaScript Program to check if a string is  // binary string or not function isBinary(s) {  for (let i = 0; i < s.length; i++) {    // Check if the character is neither   // '0' nor '1'  if (s[i] !== '0' && s[i] !== '1') {  return false;  }  }  return true; } let s = "01010101010"; console.log(isBinary(s)); 

True

Time Complexity: O(n), where n is the length of input string s.
Auxiliary Space: O(1)