BigInteger flipBit() Method in Java

Prerequisite: BigInteger Basics 
The java.math.BigInteger.flipBit(index) method returns a BigInteger which is used to flip a particular bit position in a BigInteger. This method Computes (bigInteger ^ (1<<n)). The bit at index n of binary representation of the bigInteger will be flipped. That is, if the bit position is 0 it will be converted to 1 and vice versa.
Syntax: 
 

public BigInteger flipBit(int index)

Parameter:The method accepts one parameter index of integer type and refers to the position of the bit to be flipped.
Return Value: The method returns the bigInteger after flipping its bit at position index.
Throws: The method throws an ArithmeticException when the value of index is negative.
Examples: 
 

Input: value = 2300 , index = 1 Output: 2302 Explanation: Binary Representation of 2300 = 100011111100 bit at index 1 is 0 so flip the bit at index 1 and it becomes 1. Now Binary Representation becomes 100011111110 and Decimal equivalent of 100011111110 is 2302 Input: value = 5482549 , index = 5 Output: 5482517

Below program illustrate flipBit(index) method of BigInteger.
 

/* *Program Demonstrate flipBit() method of BigInteger  */ import java.math.*; public class GFG {  public static void main(String[] args)  {  // Creating BigInteger object  BigInteger biginteger = new BigInteger("5482549");  // Creating an int i for index  int i = 5;  // Call flipBit() method on bigInteger at index i  // store the return BigInteger  BigInteger changedvalue = biginteger.flipBit(i);  String result = "After applying flipBit at index " + i +  " of " + biginteger+ " New Value is " + changedvalue;  // Print result  System.out.println(result);  } } 

After applying flipBit at index 5 of 5482549 New Value is 5482517

Reference:https://docs.oracle.com/javase/7/docs/api/java/math/BigInteger.html#clearBit(int)