模式特点：通过吧不变的行为搬到父类，去除子类中的重复代码。
程序实例：考试时使用同一种考卷（父类），不同学生上交自己填写的试卷（子类方法的实现）
package main import ( "fmt" ) type TestPaper struct { child interface{} } func (t *TestPaper) testQuestion1() { fmt.Println("杨过得到，后来给了郭靖，练成倚天剑、屠龙刀的玄铁可能是[] a.球磨铸铁 b.马口铁 c.高速合金钥 d.碳素纤维") fmt.Println("答案：", t.child.(Answers).answer1()) } func (t *TestPaper) testQuestion2() { fmt.Println("杨过、程英、陆无双铲除了情花.造成[] a.使这种植物不再害人 b.使一种珍稀物种灭绝 c.破坏了那个生物圈的生态平衡 d.造成该地区沙漠化") fmt.Println("答案：", t.child.(Answers).answer2()) } func (t *TestPaper) testQuestion3() { fmt.Println("蓝凤凰致使华山师徒、桃谷六仙呕吐不止，如果你是大夫，会给他们开什么药[] a.阿司匹林 b.牛黄解毒片 c.氟呱酸 d.让他们喝大量的生牛奶 e.以上全不对") fmt.Println("答案：", t.child.(Answers).answer3()) } type Answers interface { answer1() string answer2() string answer3() string } type TestPaperA struct { TestPaper } func NewTestPaperA() *TestPaper { paper := &TestPaper{} var answer Answers = &TestPaperA{} paper.child = answer return paper } func (t *TestPaperA) answer1() string { return "b" } func (t *TestPaperA) answer2() string { return "c" } func (t *TestPaperA) answer3() string { return "a" } type TestPaperB struct { TestPaper } func NewTestPaperB() *TestPaper { paper := &TestPaper{} var answer Answers = &TestPaperB{} paper.child = answer return paper } func (t *TestPaperB) answer1() string { return "c" } func (t *TestPaperB) answer2() string { return "a" } func (t *TestPaperB) answer3() string { return "a" } func main() { studentA := NewTestPaperA() studentA.testQuestion1() studentA.testQuestion2() studentA.testQuestion3() studentB := NewTestPaperB() studentB.testQuestion1() studentB.testQuestion2() studentB.testQuestion3() }
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