pylint-errors
R1723 (no-else-break)
Problematic code:
def foo(n: int, stop: int): for i in range(n): if i == stop: break else: yield i 
Correct code:
def foo(n: int, stop: int): for i in range(n): if i == stop: break yield i Rationale:
Used in order to highlight an unnecessary block of code following an if containing a break statement. As such, it will warn when it encounters an else following a chain of ifs, all of them containing a break statement.