我如今是一名Android Developer，大学的我曾是一名ACMer，为了不想让算法淡出我的记忆，故重拾LeetCode之Algorithm，语言选择的是Java，题库会一点点完善起来，按简单，中等，困难分类，相应难度下按题号排序，工程代码在project目录中，相关解题都在note目录中，欢迎star。
如今有机会面试Facebook，新的一轮动力刷起来，即使没进那也至少努力过了，不过Facebook每年都有机肥去面试，所以更要加油了。
| # | Title | Tag |
|---|---|---|
| 1 | Two Sum | Array, Hash Table |
| 7 | Reverse Integer | Math |
| 9 | Palindrome Number | Math |
| 13 | Roman to Integer | Math, String |
| 14 | Longest Common Prefix | String |
| 20 | Valid Parentheses | Stack, String |
| 21 | Merge Two Sorted Lists | Linked List |
| 26 | Remove Duplicates from Sorted Array | Array, Two Pointers |
| 27 | Remove Element | Array, Two Pointers |
| 28 | Implement strStr() | Two Pointers, String |
| 35 | Search Insert Position | String |
| 38 | Count and Say | String |
| 53 | Maximum Subarray | Array, Dynamic Programming, Divide and Conquer |
| 58 | Length of Last Word | String |
| 66 | Plus One | Array, Math |
| 67 | Add Binary | Math, String |
| 69 | Sqrt(x) | Binary Search, Math |
| 70 | Climbing Stairs | Dynamic Programming |
| 83 | Remove Duplicates from Sorted List | Linked List |
| 88 | Merge Sorted Array | Array, Two Pointers |
| 100 | Same Tree | Tree, Depth-first Search |
| 101 | Symmetric Tree | Tree, Depth-first Search, Breadth-first Search |
| 104 | Maximum Depth of Binary Tree | Tree, Depth-first Search |
| 107 | Binary Tree Level Order Traversal II | Tree, Breadth-first Search |
| 108 | Convert Sorted Array to Binary Search Tree | Tree, Depth-first Search |
| 110 | Balanced Binary Tree | Tree, Depth-first Search |
| 111 | Minimum Depth of Binary Tree | Tree, Depth-first Search, Breadth-first Search |
| 112 | Path Sum | Tree, Depth-first Search |
| 118 | Pascal's Triangle | Array |
| 119 | Pascal's Triangle II | Array |
| # | Title | Tag |
|---|---|---|
| 2 | Add Two Numbers | Linked List, Math |
| 8 | String to Integer (atoi) | Math, String |
| 19 | Remove Nth Node From End of List | Linked List, Two Pointers |
| # | Title | Tag |
|---|---|---|
| 4 | Median of Two Sorted Arrays | Binary Search, Array, Divide and Conquer |