[solved] regex issue

[paul18fr]

Hi

I'm spending too much time in trying to fing how to get the number between 'BEGIN' and 'END' using a pure regex: what is the correct syntax to say 'ignore up to 'BEGIN/' and get until 'END' ?
(Note the number of slash '/' differs from a case to another, so i'm not interested by 'split')

Thanks

Following trials are incomplete

line = '/blabla/bbbb/llll/aaaa/BEGIN/0555END/lalalalalala' get0 = re.findall(r'.*?(?=BEGIN)', line) get1 = re.findall(r'.*?BEGIN\/', line) get2 = re.findall(r'.*?END\/', line) get3 = re.findall(r'^[.*?BEGIN\/]*(.*)END', line) get4 = re.findall(r'.*!(?=BEGIN)*(.*)END', line)

[snippsat]

Something like this.

import re line = '/blabla/bbbb/llll/aaaa/BEGIN/0555END/lalalalalala' # capturing group f_all = re.findall(r'BEGIN/(\d+)END', line) # lookarounds (no capturing group needed) s = re.search(r'(?<=BEGIN/)\d+(?=END)', line) print(f_all) print(s.group(0))

Output:
['0555'] 0555

[paul18fr]

seems so easy ... thanks

[Pedroski55]

Lookarounds make re work harder. I think they are unnecessary here.

import re line2 = '/blabla/bbbb/llll/aaaa/BEGIN/0555END/lala/BEGIN/0555END/lalalala/BEGIN/0555END/blabla/' # lazy search pattern find anything between BEGIN/ and END/ i = re.compile(r'BEGIN/(.*?)END/') res = i.search(line2) # res.group(1) returns '0555' res = i.findall(line2) # res = ['0555', '0555', '0555']