convert to bin problem

[kucingkembar]

hi, sorry for my bad english,
i tried to create phash compare using "VideoHash"

#pip install videohash from videohash import VideoHash import time start_time = time.time() path = "input.mp4" a = VideoHash(path=path) print(a) print(type(a)) b = str(a) print(b) print("len :",len(b)) print(type(b)) c = int(b,2) print(c) print(type(c)) d = bin(c) print(d) print("len :",len(d)) print(time.time() - start_time,"Seconds")

and the result:

Output:
0b0000100100001110111000100111111101100001011000010100000000000000 <class 'videohash.videohash.VideoHash'> 0b0000100100001110111000100111111101100001011000010100000000000000 len : 66 <class 'str'> 652708032737787904 <class 'int'> 0b100100001110111000100111111101100001011000010100000000000000 len : 62 9.695210933685303 Seconds

but the number of digits after conversion is different, the original is 66, and the converted is 62,
i tried to using format( '#064b') but it for string data,
i need it because the binary needs to compare using a bitwise technique

def hamming_distance(a, b): return bin(a ^ b).count('1') print(hamming_distance(a, b))

please help me

[Gribouillis]

Conversion to int removed the zeros at the beginning. You could simply add a 1 at the beginning

s = '1'+ a[2:] c = int(s)

[kucingkembar]

Conversion to int removed the zeros at the beginning. You could simply add a 1 at the beginning

s = '1'+ a[2:] c = int(s)

thank you for the reply,
the main problem, the standard is 64-bit data,
it can be stated at 0b00, to 0b11
and the target is bin(ary) for bitwise operation

[kucingkembar]

ok, i solve it by split it by chars

for i in range(2,len(str(a))): print(str(a)[i])