Regular Expression for matching words

[xinyulon]

Hello. I'm really not sure about the defined re pattern for this exercise, especially how to define the string words between == on both sides in order to remove it as a whole header. Could you please provide me with any tips if you happen to know that. Thank you!

My exercise:

Wikipedia uses two or more equal signs == to mark headers and subheaders in the articles (e.g. ==, ===, ====).

In all cases, the equal signs and the actual header text are separated by spaces on both sides, e.g. == History == or === Further reading ===.

Import the re module and define a regular expression that removes all headers and subheaders from the articles. Store this regular expression under a variable named pattern.

Apply the regular expression under pattern to each article (string object) in the list wiki_articles. Store each processed article into a new list named cleaned_articles.


My answer:

import re cleaned_articles=[] for string_object in wiki_articles: pattern = re.compile(r'={2,}.+') #not sure about the defined pattern processed = pattern.sub(repl='', string=string_object) cleaned_articles.append(processed)

[snippsat]

You most make test strings to see what happens,and no loop before have test this first.

import re string_object = '''\ == History == === Further reading === My car is blue 2 + 2 = 4 ++= & hello=''' pattern = re.compile(r'={2,}.+') processed = pattern.sub(repl='', string=string_object) print(processed.strip())

Output:
My car is blue 2 + 2 = 4 ++= & hello=

So your regex should work fine and added .strip() to remove the new line that sub leave.