General programming question (input string)[

[jamie_01]

#!/usr/bin/python3 list_item_two = ['apples', 'oranges', 'pears', 'apricots'] list_item_two.append("celery") print("ADD (1) or REMOVE (2) elements\n") user_input = input("> ") if user_input == "1": print("Add Element to List") special_val = "add" elif user_input == "2": print("Remove Element to List") special_val = "remove" i = 1 while i < 4: # Output list for fruit in list_item_two: print(f"{i} fruit of type: {fruit}") i += 1 print("\nLength of elements: ", len(list_item_two)) input_val = input(f"What element to {special_val}? ") # if add or remove # insert element i = 1 while i < 2: if special_val == "add": list_item_two.insert(0, input_val) elif special_val == "remove": list_item_two.remove(input_val) # this works i += 1 print("Now the list is: ", list_item_two)

please, this line right here,

 list_item_two.insert(0, input_val)

Is there a better way to write so the code runs successfully, currently under Debian Linux the program is hanging after typing '1' (ADD'ing an element) after program execution. Thanks!

[bowlofred]

Your insertion while loop (line 31) has no exit unless i >= 2.

But the "add" section does not modify i. So if you enter the loop with special_val == "add", there is no way to terminate.

I don't understand why there is a while loop there at all. Is there a case where you would expect to run the insertion or removal more than one time? Why not just get rid of the while?

[BashBedlam]

@bowlofred is correct. Remove the loop and you code performs as expected.

#!/usr/bin/python3 list_item_two = ['apples', 'oranges', 'pears', 'apricots'] list_item_two.append("celery") print("ADD (1) or REMOVE (2) elements\n") user_input = input("> ") if user_input == "1": print("Add Element to List") special_val = "add" elif user_input == "2": print("Remove Element to List") special_val = "remove" i = 1 

Output:
ADD (1) or REMOVE (2) elements > 1 Add Element to List 1 fruit of type: apples 2 fruit of type: oranges 3 fruit of type: pears 4 fruit of type: apricots 5 fruit of type: celery Length of elements: 5 What element to add? grapes Now the list is: ['grapes', 'apples', 'oranges', 'pears', 'apricots', 'celery']