[Solved] How to print a dot leader.

[BashBedlam]

Does anyone know of a simpler way to display information with a dot leader?

def add_dot_leader (text) :	new_text = ''	for index in range (1, len (text), 2) :	thing_one = text [index - 1]	thing_two = text [index]	if thing_one == ' ' and thing_two == ' ' :	new_text += ' .'	else :	new_text += thing_one + thing_two	if len (new_text) < len (text) :	new_text += text [-1]	return new_text record = {'Name': 'Roy Rodgers',	'Age': 'unknown',	'Occupation': 'Retired'} print () for label, information in record.items () :	print (add_dot_leader (f'\t{label:16}{information}'))

Like this :

Output:
Name . . . . . Roy Rodgers	Age . . . . . . unknown	Occupation . . Retired

[Gribouillis]

Perhaps using the re module

import re def add_dot_leader(text): return re.sub(r' {2}', ' .', text)

Output:
Name . . . . . .Roy Rodgers Age . . . . . . unknown Occupation . . .Retired

[Larz60+]

filler = '.' print(f'{"Name ":{filler}<{20}} Ralph') print(f'{"Age ":{filler}<{20}} 102') print(f'{"Occupation ":{filler}<{20}} Farmer')

Output:
Name ............... Ralph Age ................ 102 Occupation ......... Farmer

[menator01]

record = {'Name': 'Roy Rogers', 'Age': 'unknown', 'Occupation': 'Retired'} max_label_length = max(record) for label, information in record.items(): if len(label) < len(max_label_length): space = len(max_label_length) - len(label)+2 else: space = 2 print(f'\t{label} {"."*space}{information}')

Output:
Name ........Roy Rogers	Age .........unknown	Occupation ..Retired

[BashBedlam]

Great answers! Thank you all.