How to get parent directory from existing func not user func ?

[harun2525]

i know we can make us own function for do this with several os.path functions. but if there is a any existing function for do this, i want to use it

get_parent_dir("/path/to/myapp/modules") # returns => '/path/to/myapp/'

---

my solution is

parentdir = lambda path: os.path.realpath(path + "/.." )

[nilamo]

Pathlib is the True Savior of All Things Path:

>>> import pathlib as plib >>> x = plib.Path("/path/to/myapp/modules") >>> print(x.parent) \path\to\myapp >>> x.parent WindowsPath('/path/to/myapp')

[Larz60+]

You can the parent of a function with inspect:

This combined with Nilamo's code could be the start of a useful way to create program flow graphically.

import inspect def function1():    print('Function1 called from: {}'.format(inspect.stack()[1][3])) def function3():    print('Function1 called from: {}'.format(inspect.stack()[1][3]))    function1() def function2():    print('Function2 called from: {}'.format(inspect.stack()[1][3]))    function3() def main():    function2() if __name__ == '__main__':    main()

results:

Output:
Function2 called from: main Function1 called from: function2 Function1 called from: function3 Process finished with exit code 0

[harun2525]

thanks for answers.