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Determine number of all the immediately adjacent points in python
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Determine number of all the immediately adjacent points in python
#1
I have grid of point and want to calculate number of red and blue point surrounded by each point

for example

For point( X marked )

[Image: GemLj.png]

blue points = 6

red points = 2

I want to calculate it for the whole data set
Note: I have several dataframes with different grid sizes (24*5, 12*8, etc)
Note: In some of the dataframes I have less number of points then the grid size for example grid is 24*5 but number of points are 118

red=r=1
blue=b=0

df y x r/b 4	2	0	6	12	1	10	8	1	11	5	1	7	1	0	13	5	0	7	9	1	5	4	0	7	8	1	3	16	1	15	10	1	15	8	1	3	18	0	1	16	0	11	8	1	11	2	1	1	4	0	11	14	1	11	6	1	9	20	0	7	2	1	7	5	0	6	19	0	7	23	0	3	19	0	8	2	0	9	8	1	11	9	0	11	3	0	13	15	1	2	2	0	1	2	0	6	1	0	3	3	0	11	19	0	4	1	0	3	21	0	3	17	0	9	21	0	7	21	0	15	15	1	9	23	0	14	14	0	16	14	0	12	14	0	4	22	1	2	20	0	12	20	0	6	2	0	3	23	0	14	22	1	11	22	0	5	6	0	15	22	0	7	16	0	15	18	0	5	20	0	7	6	0	7	24	0	11	24	0	3	8	1	1	20	0	11	15	0	7	10	1	14	20	0	14	9	0	12	3	0	14	2	0	10	6	0	2	8	0	16	3	0	2	14	0	12	19	0	16	21	0	16	9	0	2	21	0	10	7	0	14	3	0	14	15	0	15	17	1	11	18	1	13	19	1	3	1	0	5	5	0	8	14	1	1	10	1	6	6	0	1	13	0	13	9	0	15	2	0	9	11	1	3	12	1	12	18	0	5	3	0	9	3	1	1	5	0	9	7	0	7	11	1	8	21	0	9	17	0	4	12	0	7	18	0	3	2	0	10	2	0	6	22	0	13	2	0	3	4	0	3	22	0	5	18	1	13	14	1	11	16	1	12	24	1	16	20	0	14	18	1	4	16	0	2	22	1	9	22	0	1	22	0	10	21	0	8	23	0	2	19	0	12	1	0	12	10	1	2	13	0	10	15	1	10	19	0	14	10	0	6	9	0	4	7	0	4	3	0	10	10	0	4	10	1	2	10	1	10	11	0	2	12	0	4	19	0	10	1	0	4	15	0	16	8	0	4	8	0	2	6	0	12	4	0	2	4	0	11	4	0	13	20	0	1	24	0	15	20	0	7	22	0	9	24	0	6	8	0	10	5	0	8	8	1	10	12	1	6	11	0	10	9	0	4	11	0	12	23	0	12	17	0	4	17	0	12	13	0	12	5	1	2	15	0	12	9	0	8	1	0	6	7	0	16	11	0	10	23	0	4	4	0	3	24	0	9	12	1	16	4	0	13	6	1	9	2	1	3	20	0	15	4	0	15	14	1	13	16	1	8	4	0	5	16	0	7	20	0	1	8	0	5	24	0	9	16	1	16	6	0	13	12	0	15	16	1	5	8	1	13	18	0	11	10	1	13	22	1	4	6	0	1	18	0	9	18	0	13	17	1	13	21	0	11	23	0	1	15	0	5	21	0	5	23	0	11	21	1	9	19	0	12	11	0	14	17	0	2	11	0	8	11	0	16	12	0	2	5	0	16	1	1	16	15	0	14	1	0	8	17	0	8	7	0	4	23	0	6	3	0	14	7	0	8	15	0	12	21	0	8	13	0	2	9	0	8	9	0	16	5	0	14	11	0	2	23	0	14	5	1	6	5	0	6	13	0	4	5	0	6	23	0	8	5	0	16	7	0	16	17	1	4	14	0	12	8	0	12	12	0	6	10	1	14	12	0	16	10	0	8	12	1	14	8	0	1	19	0	5	17	0	3	15	0	9	15	0	3	13	0	11	13	1	13	13	0	13	7	1	11	7	1	13	1	1	16	16	1	10	14	1	12	22	0	6	18	0	9	4	0	3	6	1	7	14	0	3	14	0	8	6	0	5	12	1	5	11	0	6	14	1	10	16	0	4	20	1	16	18	1	8	18	0	4	24	0	6	16	1	14	16	1	13	3	0	15	11	0	15	1	0	15	3	0	5	9	0	1	17	0	1	9	0	1	1	0	7	17	0	1	21	0	10	18	0	16	22	1	6	24	0	4	18	0	2	16	0	16	2	0	15	6	0	9	14	1	5	14	1	1	14	1	3	10	0	9	10	0	8	16	0	5	10	1	9	6	0	9	13	0	15	12	0	8	20	0	1	12	0	11	12	1	8	22	0	7	12	1	13	4	0	8	24	0	13	10	1	6	20	0	8	10	1	1	6	0	5	22	0	5	2	0	2	1	0	11	11	0	15	7	0	11	1	1	9	5	1	7	7	0	15	13	1	13	11	1	5	7	0	15	21	0	10	22	1	12	2	0	14	4	0	2	24	0	12	16	1	2	18	0	15	19	0	3	11	0	5	19	0	10	24	0	11	17	0	1	23	0	3	7	0	2	17	0	4	21	0	14	13	0	6	15	0	7	13	0	10	4	0	6	21	0	6	17	0	14	21	0	16	13	0	10	13	0	15	5	0	10	17	0	5	15	0	7	3	0	2	7	0	4	13	0	3	9	1	10	3	0	15	9	0	2	3	0	12	15	0	16	19	0	7	15	0	12	6	0	8	19	0	4	9	0	5	1	0	1	7	0	1	3	0	9	1	0	5	13	0	1	11	0	9	9	0	12	7	0	13	8	1 14	6	0 15	23	0 16	23	0 15	24	0 16	24	0 13	23	1 14	23	1 13	24	1 14	24	1 7	4	0 11	20	1 6	4	1 10	20	1 8	3	1 14	19	0 3	5	1 7	19	1
color_matrix=df["r/b"].values.reshape(24, 16) #since this dataframe has grid size 24*16 from scipy import signal adjacent_boxes = np.array([[1,1,1], [1,0,1], [1,1,1]]) red_dots = signal.convolve2d(color_matrix, adjacent_boxes , mode='same', boundary='fill') blue_dots = signal.convolve2d(1 - color_matrix, adjacent_boxes , mode='same', boundary='fill') df['red_dots'] = red_dots.flatten() df['blue_dots'] = blue_dots.flatten()
this code has issue as 1st col= y axis, 2nd col= x axis, show the coordinates of each point and they are not in the sequence , but simply doing .reshape(num_rows, num_cols) will create 2D array as it is sequenced in the dataframa (col3)

Final goal is to have df with
y x r/b red_dots blue_dots
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#2
any one ??
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