Reverse a String

[ragav_in]

HI team,

This is my first post since I started learning Python now and came to know about this forum. Hence I reached out here to get clarifications.

I need to reverse a string and print it, and I have written a code. But it is not complete and prints a different answer when I give the input. I think the loop (i = i + 1) is not executed properly and hence its printing only the alphabhet 'c'. I am not sure of what I am missing here.

May I kindly request this forum to help me fix this issue. I am thankful to you for the effort you have taken for reading thi post.

def reverse(s): '''(str) -> str Return the reverse of s. >>> reverse('abc') 'cba' ''' str_change = '' i = len(s) - 1 while i >= 0: str_change = str_change + s[i] i = i + 1 return result

Thanks,
ragav

[scidam]

You need backward iterations over the string here, why do you increment i? (i=i+1)

[bowlofred]

Looks pretty close.

If you're going from the back of the list, then you need to decrement the index, not increment it.

Also, you're working with str_change in the loop, but then at the end you try to return result.

Fix those two things and it should be functional.

[ragav_in]

All, thanks much for your effort to review the same and provide inputs. I am sorry that my post was not as per the Forum expectation, but since I am new to this, the mistake happened. I will ensure that this does not happen in future. I am giving the full code here, but still I get error and not the correct ouput. When I write this code and compile it and run my input in the Python Shell, I get error for this input. And for some reason, I am unable to get the indentation when I post the code (it is indented properly in my shell).

I want to reverse the below string:

reverse ('abc')

Error message I get:

Error:
Traceback (most recent call last): File "<pyshell#18>", line 1, in <module> reverse('abc') File "Final_Miss.py", line 430, in reverse str_change = str_change + s[i] IndexError: string index out of range

My code snippet:

def reverse(s): '''(str) -> str Return the reverse of s. >>> reverse('abc') 'cba' ''' str_change = '' i = len(s) - 1 while i >= 0: str_change = str_change + s[i] i = i + 1 return str_change