comparing 2 dimensional list

[glennford49]

i have this code:

 num1=[[1,2,3],[1,2,4],[1,2,5]] num2=[[1,2,3]] for i in num1: if (num2 == i): print("same")	else: print("unique")

whats wrong with my code?
num1 has 3 elements, num2 has single element with same value element of num1,
it should print "same" on output since num2 has a the same value element on num1

[Larz60+]

first you didn't define i
you don't understand indexing. See: https://docs.python.org/3/tutorial/datastructures.html

[glennford49]

Im sorry im a noob in coding, i just cant figure it out , so that it will print "unique" in the output

[Larz60+]

you can use:

if [1,2,3] in num1: print("it is") else: print("Not found")

[perfringo]

On row #5 You compare item (list) in first matrice (list of lists) with whole second matrice. They can’t be equal. You could use indexing to refer to item in second matrice (num2[0]) in comparison.

[glennford49]

Thanks for your response,maybe comparing those 2 list is of no solution, in my code ,num2 data on it is changing, thats why in my mind i have to iterate num1 list of list , and compare num2 if there's the same value on num1

[perfringo]

I probably don't understand the problem, but anyway:

>>> num1=[[1,2,3],[1,2,4],[1,2,5]] >>> num2=[[1,2,3]] >>> for i, item in enumerate(num1, start=1): ... if item == num2[0]: ... print(f'item no {i} is equal') ... else: ... print(f'item no {i} is not equal') ... item no 1 is equal item no 2 is not equal item no 3 is not equal

[glennford49]

I probably don't understand the problem, but anyway:

>>> num1=[[1,2,3],[1,2,4],[1,2,5]] >>> num2=[[1,2,3]] >>> for i, item in enumerate(num1, start=1): ... if item == num2[0]: ... print(f'item no {i} is equal') ... else: ... print(f'item no {i} is not equal') ... item no 1 is equal item no 2 is not equal item no 3 is not equal

thanks, this saves my day!

[DeaD_EyE]

num2 should be a list and not a list in a list.

Your original code with the change:

num1 = [[1,2,3], [1,2,4], [1,2,5]] num2 = [1,2,3] for i in num1: if (num2 == i): print("same") else: print("unique")

Output:
same unique unique

[glennford49]

num2 should be a list and not a list in a list.

Your original code with the change:

num1 = [[1,2,3], [1,2,4], [1,2,5]] num2 = [1,2,3] for i in num1: if (num2 == i): print("same") else: print("unique")

Output:
same unique unique

Nothing has change i think