Return all Values which can divided by 9

[lastyle]

Hi all

i am searching for a funtion or simmilar solution that returns if a value can be divided by 9 without rest.

I was trying with Modulo operation but this didnt give me the correct result

for number in range(1, 3500): if(number % 9 != 0): print(number)

Anybody who might help me out with guiding to the correct Solution or giving a hint what i am searching for ?

Thanks in Advancee

[scidam]

I can give you a hint. If a number n is divisible by m without rest, n % m = 0.
Try the following examples

9 % 9 18 % 9 27 % 9

Hope this helps.

[lastyle]

I can give you a hint. If a number n is divisible by m without rest, n % m = 0.
Try the following examples

9 % 9 18 % 9 27 % 9

Hope this helps.

Yep, thx a lot, didnt work directly but

for number in range(1, 3000): if(number % 9 == 0): print(number)

did the trick