Naughts and Crosses win check

[GalaxyCoyote]

I was wondering how I would make a Win checker for my Naughts and Crosses game (Tic Tac Toe).

I am using lists

Row1 = ["-","-","-"] Row2 = ["-","-","-"] Row3 = ["-","-","-"] Loop = True #Loop Turn = 0 #Flips between Player 1 and Player 2 Pinput = 0 #Player input def check(): print("checkerhere")

the def check(): is where I want the checker to be.
If any of you could point me in the right direction that would be great!

[jefsummers]

You only need to check if the last move created a win. So, assume last move was by X
Check to see if all in that row are X
Check to see if item in each row in that position are X (check columns)
If the position is a corner or the middle, check diagonals.

[ichabod801]

It's also easier if you use a list of lists:

board = [['-', '-', '-'], ['-', '-', '-'], ['-', '-', '-']]

That way you can use incremental indexing to go through the rows, the columns, and the diagonals.

[perfringo]

The 'check' function should return True or False regarding win.

Some ideas that might be useful: use set() or all() to determine whether there is 'all-spam' situation:

>>> m = ['spam spam spam'.split(), 'spam ham spam'.split()] >>> m [['spam', 'spam', 'spam'], ['spam', 'ham', 'spam']] >>> for row in m: ... print(set(row) == {'spam'}) ... True False >>> for row in m: ... print(all(mark == 'spam' for mark in row)) ... True False

To make it more useful any() could be added - to determine is there at least one row with 'all-spam':

>>> any(set(row) == {'spam'} for row in m) True >>> any(all(mark == 'spam' for mark in row) for row in m) True