can you understand why this code prints None?

[arcbal]

# assuming n is always greater than m def fd(n,m): if n%m==0: print(m) return m else: print(n,m) fd(n,(m-1)) print(fd(6,5))

the result is not what i expect,i expect

Output:
6,5 6,4 3 3

but the result i get is:

Output:
6,5 6,4 3 None

i don't why this None is occurring??

[ichabod801]

If n % m == 0, then there is a return statement. But if n % m != 0, there is no return statement. In that case, the default return of None is done by Python. You probably want line 8 to be:

return fd(n, m - 1) # you don't need parentheses for m - 1.

[arcbal]

you are awesome,thanks.

---

If n % m == 0, then there is a return statement. But if n % m != 0, there is no return statement. In that case, the default return of None is done by Python. You probably want line 8 to be:

 return fd(n, m - 1) # you don't need parentheses for m - 1. 

you are the best, thanks.