Posts: 39 Threads: 14 Joined: Oct 2018 List = [[0,1,2],[4,5,6,7],[7,8,9,10]] def ReplacewithMax (l, count = 0, L = None): if count == 0: L = [] K = [] for i in l[count]: K.append(max(l[count])) L.append(K) count += 1 return ReplacewithMax(l,count,L) if count < len(l): K = [] for i in l[count]: K.append(max(l[count])) L.append(K) count += 1 return ReplacewithMax(l,count,L) if count == len(l): return L K = ReplacewithMax(List) print (K) I have a nested list. In the second level, I want to replace theirs item with the maximum value in each list. The code I post achieved the goal. But I'm seeking for a simpler way to do that. Thanks! Posts: 12,117 Threads: 494 Joined: Sep 2016 Quote:replace theirs item ?? Posts: 1,953 Threads: 8 Joined: Jun 2018 Maybe something like this: >>> List = [[0,1,2],[4,5,6,7],[7,8,9,10]] >>> [[max(row) for el in row] for row in List] [[2, 2, 2], [7, 7, 7, 7], [10, 10, 10, 10]] I'm not 'in'-sane. Indeed, I am so far 'out' of sane that you appear a tiny blip on the distant coast of sanity. Bucky Katt, Get Fuzzy
Da Bishop: There's a dead bishop on the landing. I don't know who keeps bringing them in here. ....but society is to blame. Posts: 2,167 Threads: 35 Joined: Sep 2016 Another my_list = [[0,1,2],[4,5,6,7],[7,8,9,10]] new_list = [[max(each)]*len(each) for each in my_list] print(new_list) Output: [[2, 2, 2], [7, 7, 7, 7], [10, 10, 10, 10]]
Posts: 39 Threads: 14 Joined: Oct 2018 (Mar-11-2019, 09:12 PM)Yoriz Wrote: Another
my_list = [[0,1,2],[4,5,6,7],[7,8,9,10]] new_list = [[max(each)]*len(each) for each in my_list] print(new_list) Output: [[2, 2, 2], [7, 7, 7, 7], [10, 10, 10, 10]]
Thanks, that is very helpful |
