is there equal syntax to "dir /s /b"

is there equal syntax to "dir /s /b" - Printable Version

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is there equal syntax to "dir /s /b" - kucingkembar - Aug-16-2022

sorry for my bad English,
currently i looking all files in a folder and subfolder like "dir /s /b" in windows-cmd

D:\test>dir /s /b D:\test\test D:\test\test (2).py D:\test\test.py D:\test\test\test.py

is there any equal syntax like this in python?
Note:
I know code

import os for text in os.listdir(): print(text)

but that only show files name, I need full path

RE: is there equal syntax to "dir /s /b" - Pedroski55 - Aug-16-2022

]Try glob??

import glob path = '/home/pedro/summer2021/OMR/' files = glob.glob(path + '/**', recursive=True) for f in files: # shows all paths and files in path print(f)

or like this:

from pathlib import Path mydir = Path(path) path2python = '/home/pedro/summer2021/OMR/python/' mydir = Path(path2python) filelist = [filename for filename in mydir.iterdir() if filename.is_file()] for filename in filelist: print(f"\nfilename: {filename.name}") print(f"file suffix: {filename.suffix}") print(f"full path: {filename.resolve()}") print(f"filepath parts: {filename.parts}")

import os for root,dirs,files in os.walk(path): print('root is:', root) print('dirs is:', dirs) print('files are:', files) for file in files: print(os.path.join(root, file))

If I remember correctly, I got all this from snippsat, so please say thank you to him, not me!

RE: is there equal syntax to "dir /s /b" - kucingkembar - Aug-16-2022

(Aug-16-2022, 07:54 AM)Pedroski55 Wrote: ]Try glob??

import glob path = '/home/pedro/summer2021/OMR/' files = glob.glob(path + '/**', recursive=True) for f in files: # shows all paths and files in path print(f)

or like this:

from pathlib import Path mydir = Path(path) path2python = '/home/pedro/summer2021/OMR/python/' mydir = Path(path2python) filelist = [filename for filename in mydir.iterdir() if filename.is_file()] for filename in filelist: print(f"\nfilename: {filename.name}") print(f"file suffix: {filename.suffix}") print(f"full path: {filename.resolve()}") print(f"filepath parts: {filename.parts}")

import os for root,dirs,files in os.walk(path): print('root is:', root) print('dirs is:', dirs) print('files are:', files) for file in files: print(os.path.join(root, file))

If I remember correctly, I got all this from snippsat, so please say thank you to him, not me!

thank you Pedroski55. i will give you reputation point

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