TCS Coding Problem 7

25 comments on “TCS Coding Problem 7”

• 
  

  amit

  #include
  #include
  int sum_of_digit(int);
  int main()
  {
  char num[20];
  int l,j,res=0,sum=0;
  gets(num);
  l=strlen(num);
  for(int i=0;i0)
  {
  m=sum%10;
  store=store+m;
  sum=sum/10;
  }
  return store;
  }

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• 
  

  17E11A04A1

  #python
  g=int(input(“enter the number”))
  amg=g
  sum=0
  while amg!=0:
  a=amg%10
  b=a**3
  amg=amg//10
  sum=sum+b
  if g==sum:
  print(sum,”its an amstrong”)
  else:
  print(sum,”not amstrong”)

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• 
  

  Raman

  #include

  int main() {
  int num,n;
  int sum=0,i,rem;

  scanf(“%d”,&num);
  scanf(“%d”,&n);

  int temp=num;

  for(i=1;i<=n;i++){
  rem=num%10;
  sum=sum+(rem*rem*rem);
  num=num/10;
  }
  if(sum==temp){
  printf("Its a armstrong number");
  }
  else{
  printf("Its not a armstrong number");
  }

  return 0;
  }

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• 
  

  Pogakula

  #python3
  def armstrong(s):
  return sum([int(i)**len(str(s)) for i in str(s)])==s
  num=int(input(‘enter the number:\t’))
  print(armstrong(num))

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• 
  

  swapnil

  num = int(input())
  numvalue=num
  arr = []
  while num > 0:
  l = num % 10
  num = num – l
  arr.append(l)
  num = num // 10
  res = 0
  for i in arr:
  p = 1
  for j in range(len(arr)):
  p = p * i
  res+=p
  if(res==numvalue):
  print(“Yes”)
  else:
  print(“no”)

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• 
  

  swapnil

  public static void main(String[] args) {
  // TODO Auto-generated method stub
  Scanner s=new Scanner(System.in);
  String s1=s.nextLine();
  String[] s2=s1.split(“”);
  int j=0;
  int[] arr=new int[s2.length];
  for(String i:s2) {

  arr[j]=Integer.parseInt(i);
  j+=1;
  }
  int sum=0;
  int prod=1;
  for(int i:arr) {
  prod=1;

  for(int k =0;k<arr.length;k++) {
  prod=prod*i;

  }

  sum=sum+prod;

  }

  if(sum==Integer.parseInt(s1)) {
  System.out.println("YES");

  }else {
  System.out.println("NO");
  }
  }

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• 
  

  swapnil

  public static void main(String[] args) {
  // TODO Auto-generated method stub
  Scanner s=new Scanner(System.in);
  String s1=s.nextLine();
  String[] s2=s1.split(“”);
  int j=0;
  int[] arr=new int[s2.length];
  for(String i:s2) {

  arr[j]=Integer.parseInt(i);
  j+=1;
  }
  int sum=0;
  for(int i:arr) {

  sum=sum+(i*i*i);

  }

  if(sum==Integer.parseInt(s1)) {
  System.out.println(“YES”);

  }else {
  System.out.println(“NO”);
  }
  }

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• 
  

  The Bong

  public class ArmstrongNumber {
  public static void main(String[] args) {
  System.out.println(checkArmstrong(153));
  System.out.println(checkArmstrong(1253));
  }
  static boolean checkArmstrong(int number) {
  int temp = number;boolean isArmstrong = false;
  int sum = 0;
  while (temp > 0) {
  int remainder = temp % 10;
  sum += (int)Math.pow(remainder, Integer.toString(number).length());
  temp /= 10;
  }
  if(sum == number) {
  isArmstrong = true;
  }
  return isArmstrong;
  }
  }

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• 
  

  The Bong

  public class ArmstrongNumber {
  public static void main(String[] args) {
  System.out.println(checkArmstrong(153));
  System.out.println(checkArmstrong(1253));
  }
  static boolean checkArmstrong(int number) {
  int temp = number;boolean isArmstrong = false;
  int sum = 0;
  while (temp > 0) {
  int remainder = temp % 10;
  sum += remainder*remainder*remainder;
  temp /= 10;
  }
  if(sum == number) {
  isArmstrong = true;
  }
  return isArmstrong;
  }
  }

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• 
  

  kandukuri

  #include
  #include

  void armstrong(int a, int count)
  {
  int demo = a;
  int sum = 0, digit1;
  while (a > 0)
  {
  digit1 = a % 10;
  sum = sum + pow(digit1, count);
  a = a / 10;
  }
  if (sum == demo)
  {
  printf(“yes”);
  }
  else
  {
  printf(“no”);
  }
  }

  void main()
  {
  int num, digit, count = 0, n;
  printf(“please enter the num: “);
  scanf(“%d”, &num);
  int demonum = num;
  while (num > 0)
  {
  digit = num % 10;
  count++;
  num = num / 10;
  }
  armstrong(demonum, count);
  }

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• 
  

  abhijeet singh

  ********************************very easy c++ program**************************
  #include
  #include
  using namespace std;
  int main()
  {
  int origNum, num, rem,count=0;
  cout <> origNum;
  num = origNum;
  while(num != 0)
  {
  rem = num % 10;
  num /= 10;
  count++;
  }
  num=origNum;
  rem=1;
  int sum=0;

  while(num!=0)
  {rem=num%10;
  sum=sum+pow(rem,count);
  num /= 10;
  }
  if(sum==origNum)
  {
  cout<<"armstrong no";

  }
  }

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• 
  

  Meghana

  u gave in a different process.
  for armstrong there is a method to execute.please provide as easy as possible.it is a loss for the paid material members like me

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• 
  

  Mohd Saif

  # python ? Meghana

  n=int(input())
  y=len(str(n))
  temp==n
  x=0
  while(n>0):
  a=n%10
  x=x+pow(a,y)
  n=n//10
  if(temp==x):
  print(f”YES {temp} is a Armstrong Number”)
  else:
  print(f”NO {temp} is a Armstrong Number”)

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