TCS Coding Problem 7

25 comments on “TCS Coding Problem 7”

• 
  

  sai

  import math
  def isAmstrong(num):
  n = len(str(num))
  t=n
  temp = num
  total=0
  while t>0:
  digi = num % 10
  total += math.pow(digi,n)
  num = num//10
  t-=1
  if total == temp:
  return “yes”
  else:
  return “No”

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• 
  

  156

  package workspace;

  import java.util.Scanner;

  public class armstrong {

  public static void main(String[] args) {

  Scanner scn=new Scanner(System.in);
  int n=scn.nextInt();
  int temp=n;
  int node=0;
  int sum=0;
  while(temp>0) {
  node++;
  temp=temp/10;
  }

  temp=n;
  while(temp>0) {
  int val=1;
  int rem=temp%10;
  for(int i=1;i<=node;i++) {
  val=val*rem;
  }
  sum=sum+val;
  temp=temp/10;
  }
  if(sum==n) {
  System.out.println("YES");
  }else {
  System.out.println("NO");
  }

  }

  }

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• 
  

  sagarbiswasbunny

  def armstrong_number(num):
  num_list=list(map(int,str(num)))
  n=len(num_list)
  sum_num=0
  for i in range(n):
  sum_num=sum_num+num_list[i]**n
  if sum_num==num:
  return True
  else:
  return False

  num=int(input())
  print(armstrong_number(num))

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• 
  

  RAKESH

  //java
  import java.util.Scanner;

  public class ArmstrongNumber {

  public static void main(String[] args) {
  Scanner sc=new Scanner(System.in);
  int n=sc.nextInt();
  String s=String.valueOf(n);
  int x=0;

  for(int i=0;i<s.length();i++)
  {
  x=x+(int) Math.pow(Integer.valueOf(String.valueOf(s.charAt(i))),s.length() );
  }
  if(x==n)
  {
  System.out.print(n+" is Armstrong Number");
  }
  else
  {
  System.out.print(n+" is not Armstrong Number");
  }
  }

  }

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• 
  

  dee.pansh18johri

  #include
  using namespace std;
  int main() {
  // your code goes here
  int n;
  cin>>n;
  int len=0;
  int m=n;
  while(m)
  {
  len++;
  m/=10;
  }
  double sum=0;int w=n;
  while(n)
  {
  sum+=pow(n%10,len);
  n/=10;
  }
  if(sum==w)
  cout<<"ARMSTRONG";
  else
  cout<<"NOT AN ARMSTRONG NUMBER";
  return 0;
  }
  // O(N)

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• 
  

  Adarsh

  #include
  #include
  using namespace std;

  int main()
  {
  int n;
  cin>>n;
  int count=0;
  int temp=n;
  int t,temp1,tot=0;
  while(temp>0)
  {
  temp=temp/10;
  count++;
  }

  t=n;
  for(int i=0;i<count;i++)
  {
  temp1=t%10;

  tot=tot+pow(temp1,count);
  t=t/10;

  }

  if(tot==n)
  { cout<<n<<" is an armstrong number";}
  else { cout<<n<<" is not an armstrong number";}
  }

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• 
  

  Adarsh

  #c++ 17
  #include and

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• 
  

  Gourav

  n=16345
  temp=n
  lng=0
  while(temp!=0):
  temp=temp//10
  lng+=1
  temp=n
  res=0
  while(temp!=0):
  res=res+pow(temp%10,lng)
  temp=temp//10
  if(res==n):
  print(‘YES’)
  else:
  print(‘NO’)

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• 
  

  Deepak

  #include
  #include
  using namespace std;
  int main()
  {
  int n,sum=0,r;
  cout<>n;
  int size = trunc(log10(n)) + 1;
  cout<<size<0)
  {
  r=n%10;
  n=n/10;
  sum=sum+pow(r,size);
  }
  if(sum==temp)
  {
  cout<<temp<<" is armstrong number";
  }
  else
  cout<<temp<<" is not armstrong number";

  }

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• 
  

  Rohan

  #include
  #include
  #include
  int main()
  {
  int n, i,d=0, num,c=0,k, an=0;
  printf(“Enter anumber”);
  scanf(“%d”,&n);
  num=n;
  k=n;
  printf(“%d\n”,k);
  while(n!=0)
  {

  n=n/10;
  c++;
  }

  while(k!=0)
  {
  d= k%10;

  an += pow(d,c) ;

  k=k/10;
  }
  printf(“%d”,an);
  if(num == an)
  printf(“It is armstrong number”);
  else
  printf(“It is not a armstrong number”);
  return 0;

  }

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• 
  

  shushank

  n=int(input())
  a=n
  c=0
  d=len(str(n))
  while n!=0:
  c1=n%10
  c=c+c1**d
  n=n//10
  if a==c:
  print(“Yes”)
  else:
  print(“No”)

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• 
  

  Debanjan

  import math
  def checkArmstrong(n) :
  l=len(n)
  print(l)
  a=int(n)
  print(a)
  b=a
  e=0
  while a>0:
  d=a%10
  e=e+d**l
  a=math.trunc(a/10)
  print(e)
  if e==b:
  return True
  else:
  return False
  # n=input(“Enter number to be checked”)
  print(checkArmstrong(“153”))

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