Problem 13

9 comments on “Problem 13”

• 
  

  Gourav

  n=int(input())
  res=0
  temp=n
  lenn=0
  while(temp!=0):
  lenn+=1
  temp=temp//10
  for i in range(lenn):
  res=res*(10)+n%10
  n=n//10
  print(res)

  Log in to Reply
• 
  

  Vaibhav

  Python:
  num=str(input())
  print(num[::-1]

  Log in to Reply
• 
  

  shushank

  #PYTHON
  n=int(input())
  c=0
  while n!=0:
  a1=n%10
  c=c*10+a1
  n=n//10
  print(c)

  Log in to Reply
• 
  

  Sunny

  n=int(input())
  rev=[]
  for i in str(n):
  rev.append(int(i))
  reverse_final=rev[::-1]
  for i in range(len(reverse_final)):
  print(reverse_final[i],end=””)

  Log in to Reply
• 
  

  Raman

  // Online C compiler to run C program online
  #include

  int main() {
  int n,rem,c=0,i=0;
  int a[20];
  scanf(“%d”,&n);
  while(n>0){
  rem=n%10;
  a[i]=rem;
  n=n/10;
  i++;
  c++;
  }
  for(i=0;i<c;i++){
  printf("%d",a[i]);
  }

  return 0;
  }

  Log in to Reply
• 
  

  Richik

  PYTHON 3:
  k=0
  i=0
  def rev(n):
  global k
  global i
  if n==0:
  return
  else:
  rev(n//10)
  k+=(n%10)*10**i
  i+=1
  rev(int(input()))
  print(k)

  Log in to Reply
• 
  

  Harsha

  def reverse(n):
  str_n=str(n)
  if n<0:
  str_n=str_n[1:]
  str_n=str_n[::-1]
  str_n='-'+str_n
  else:
  str_n=str_n[::-1]
  return int(str_n)
  n=int(input())
  print(reverse(n))

  Log in to Reply
• 
  

  avi gehlot

  #python code here
  number =int(input())
  reverse=0
  while number>0:
  remainder=number%10
  reverse=reverse*10+remainder
  number=number//10
  print(reverse)

  Log in to Reply
• 
  

  Taha

  #PYTHON
  n= input()
  print(reversed(n))

  Log in to Reply