Linked Questions

0 votes
1 answer
411 views

Let $u$ be a function such that $|u|^{(p-2)/2}u$ is in $H^1_0(G)$, $G$ is open and $p>2$. How can I show that $$ D(|u|^{(p-2)/2}u)=p/2|u|^{(p-2)/2}D(u) \label{1}\tag{1} $$ or how can I show that, ...
Perelman's user avatar
  • 163
4 votes
1 answer
244 views

Let us define the density of subset $A\subset\omega$ : $$\rho(A)=\lim_{n\to\infty}\frac{|A\cap n|}{n}$$ if the limit exists. Let $\mathcal{F_1}=\{A\subset\omega~|~\rho(A)=1\}$. $\mathcal{F_1}$ is the ...
ar.grig's user avatar
  • 1,153
7 votes
0 answers
477 views

There is a folklore conjecture that $\operatorname{Ext}^2$ vanishes in the category of geometric $p$-adic Galois representations (i.e. representations that are unramified almost everywhere and de Rham ...
David Corwin's user avatar
  • 15.9k
4 votes
0 answers
497 views

I was always thinking, in an informal way, that the powerset lattices ${\cal P}(X)$ (where $X$ is an infinite set) are the "widest" bounded distributive lattices with respect to their height. (In ${\...
Dominic van der Zypen's user avatar
1 vote
0 answers
404 views

I am looking for a list of mathematical technicalities that are not so well-known, even in the mathematical community. What I mean is, I am looking for examples of phenomenon where it is important to ...
0 votes
0 answers
284 views

Here, Martin Brandenburg says it is not true that "Every short exact sequence of the form $0 \to A \to A \oplus B \to B \to 0$ splits." Then Mohan says in comments that "As a positive result, If $0 ...
user 1's user avatar
  • 1,407
1 vote
0 answers
233 views

In the survey paper Poset Topology: Tools and Applications by Michelle Wachs, there is the following theorem on p46: Theorem 3.2.4 (Björner and Wachs [40]). Suppose $P$ is a poset for which $\...
Sebastien Palcoux's user avatar
6 votes
0 answers
169 views

I am looking for an example of a topological group $G$ acting by homeomorphisms on a metrizable space $X$ such that the orbit map $X\to X/G$ doesn't have the path lifting property, that is, there is a ...
Igor Belegradek's user avatar

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