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Dec 27, 2024 at 14:48 comment added Steven Clark If $b(1)\ne0$ and $b^{-1}(n)$ is the Dirichlet inverse of $b(n)$, then $a(n)$ can be evaluated as the Dirichlet convolution $a(n)=c(n) * b(n)$ where $c(n)$ is the Dirichlet convolution $c(n)=a(n) * b^{-1}(n)$ . There is no requirement for $a(n)$ to be multiplicative.
Dec 27, 2024 at 8:49 comment added GH from MO Every arithmetic function $f$ can be decomposed into a convolution. For example, $f=1\ast g$, where $g:=\mu\ast f$. So you need to be more specific about what you want.
Dec 27, 2024 at 7:37 history edited Khadija Mbarki CC BY-SA 4.0
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Dec 26, 2024 at 19:41 comment added Khadija Mbarki Yes it is and what are these functions?
Dec 26, 2024 at 19:24 comment added Steven Clark If you mean Dirichlet convolution then I believe the answer to your question is yes.
Dec 26, 2024 at 8:07 history asked Khadija Mbarki CC BY-SA 4.0