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I found the following formula in "INTEGRALS AND SERIES, vol.3" by Prudnikov, Brychkov and Marichev (page 188, eq.5).

$$\int_0^{\infty} \frac{x^{\alpha-1}}{\sqrt{(a+x)^2+z^2}}K(\frac{2\sqrt{ax}}{\sqrt{(a+x)^2+z^2}})dx = \frac{\sqrt{\pi}}{4}\Gamma(\frac{a}{2})\Gamma(\frac{1-a}{2})(a^2+z^2)^{(\alpha-1)/2}P_{-\alpha}(\frac{z}{\sqrt{a^2+z^2}})$$$$\int_0^{\infty} \frac{x^{\alpha-1}}{\sqrt{(a+x)^2+z^2}}K(\frac{2\sqrt{ax}}{\sqrt{(a+x)^2+z^2}})dx = \frac{\sqrt{\pi}}{4}\Gamma(\frac{\alpha}{2})\Gamma(\frac{1-\alpha}{2})(a^2+z^2)^{(\alpha-1)/2}P_{-\alpha}(\frac{z}{\sqrt{a^2+z^2}})$$

$K$: complete elliptic integral of the first kind.

$\Gamma$: Gamma function

$P$: Legendre function of the first kind.

$\alpha$: complex value

The book says this is valid for $a>0, Re\{z\}>0, 0 < Re\{\alpha\}<1$. Could anybody tell me how this can be derived ?

I think this formula would be useful for evaluating Mellin transform of a function that contains the complete elliptic integrals.

Thank you in advance.

https://www.researchgate.net/publication/268650078_Integrals_and_Series_Volume_3_More_Special_Functions

I found the following formula in "INTEGRALS AND SERIES, vol.3" by Prudnikov, Brychkov and Marichev (page 188, eq.5).

$$\int_0^{\infty} \frac{x^{\alpha-1}}{\sqrt{(a+x)^2+z^2}}K(\frac{2\sqrt{ax}}{\sqrt{(a+x)^2+z^2}})dx = \frac{\sqrt{\pi}}{4}\Gamma(\frac{a}{2})\Gamma(\frac{1-a}{2})(a^2+z^2)^{(\alpha-1)/2}P_{-\alpha}(\frac{z}{\sqrt{a^2+z^2}})$$

$K$: complete elliptic integral of the first kind.

$\Gamma$: Gamma function

$P$: Legendre function of the first kind.

$\alpha$: complex value

The book says this is valid for $a>0, Re\{z\}>0, 0 < Re\{\alpha\}<1$. Could anybody tell me how this can be derived ?

I think this formula would be useful for evaluating Mellin transform of a function that contains the complete elliptic integrals.

Thank you in advance.

https://www.researchgate.net/publication/268650078_Integrals_and_Series_Volume_3_More_Special_Functions

I found the following formula in "INTEGRALS AND SERIES, vol.3" by Prudnikov, Brychkov and Marichev (page 188, eq.5).

$$\int_0^{\infty} \frac{x^{\alpha-1}}{\sqrt{(a+x)^2+z^2}}K(\frac{2\sqrt{ax}}{\sqrt{(a+x)^2+z^2}})dx = \frac{\sqrt{\pi}}{4}\Gamma(\frac{\alpha}{2})\Gamma(\frac{1-\alpha}{2})(a^2+z^2)^{(\alpha-1)/2}P_{-\alpha}(\frac{z}{\sqrt{a^2+z^2}})$$

$K$: complete elliptic integral of the first kind.

$\Gamma$: Gamma function

$P$: Legendre function of the first kind.

$\alpha$: complex value

The book says this is valid for $a>0, Re\{z\}>0, 0 < Re\{\alpha\}<1$. Could anybody tell me how this can be derived ?

I think this formula would be useful for evaluating Mellin transform of a function that contains the complete elliptic integrals.

Thank you in advance.

https://www.researchgate.net/publication/268650078_Integrals_and_Series_Volume_3_More_Special_Functions

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Derivation of an integral containing the complete elliptic functionintegral of the first kind

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Derivation of an integral containing the complete elliptic function of the first kind

I found the following formula in "INTEGRALS AND SERIES, vol.3" by Prudnikov, Brychkov and Marichev (page 188, eq.5).

$$\int_0^{\infty} \frac{x^{\alpha-1}}{\sqrt{(a+x)^2+z^2}}K(\frac{2\sqrt{ax}}{\sqrt{(a+x)^2+z^2}})dx = \frac{\sqrt{\pi}}{4}\Gamma(\frac{a}{2})\Gamma(\frac{1-a}{2})(a^2+z^2)^{(\alpha-1)/2}P_{-\alpha}(\frac{z}{\sqrt{a^2+z^2}})$$

$K$: complete elliptic integral of the first kind.

$\Gamma$: Gamma function

$P$: Legendre function of the first kind.

$\alpha$: complex value

The book says this is valid for $a>0, Re\{z\}>0, 0 < Re\{\alpha\}<1$. Could anybody tell me how this can be derived ?

I think this formula would be useful for evaluating Mellin transform of a function that contains the complete elliptic integrals.

Thank you in advance.

https://www.researchgate.net/publication/268650078_Integrals_and_Series_Volume_3_More_Special_Functions