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Aug 5, 2020 at 12:08 history edited vidyarthi CC BY-SA 4.0
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Jul 31, 2020 at 22:48 history edited vidyarthi CC BY-SA 4.0
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Jul 31, 2020 at 22:13 comment added Ruy Let us continue this discussion in chat.
Jul 31, 2020 at 21:46 history edited vidyarthi CC BY-SA 4.0
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Jul 31, 2020 at 21:30 comment added vidyarthi @Ruy thanks. edited the post. see now
Jul 31, 2020 at 21:29 history edited vidyarthi CC BY-SA 4.0
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Jul 31, 2020 at 19:46 comment added Ruy Stochastic matrices must have nonnegative entries (which often represent transition probabilities).
Jul 31, 2020 at 19:37 comment added vidyarthi @Ruy as I said, the discussion in the second discussion applies to unscaled matrices, that is, the row and column sums are same for the matrix. The matrix you gave as an example is definetely doubly stochastic. The row and column sums are all $1$
Jul 31, 2020 at 17:23 comment added Ruy I think this is not yet correct. The matrix $ E={1\over30}\pmatrix{ 25& -5& 10 \cr -5& 25& 10 \cr 10& 10& 10} $ is idempotent and has $(1,1,1)$ as a fixed point and yet it is not doubly-stochastic.
Jul 31, 2020 at 13:21 history edited vidyarthi CC BY-SA 4.0
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Jul 31, 2020 at 1:22 comment added Ruy I think I can prove that your conclusion is corrrect, but the proof is a bit envolving. Will try to write it down soon.
Jul 31, 2020 at 1:03 comment added Ruy Now I should say that I do not see why 𝑈, 𝐷, and 𝐸 must be scalar multiples of doubly stochastic matrices.
Jul 30, 2020 at 21:33 comment added vidyarthi @Ruy yes, they need not be. Added the scaling factors
Jul 30, 2020 at 21:22 history edited vidyarthi CC BY-SA 4.0
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Jul 30, 2020 at 21:14 comment added Ruy I do not see why $U$, $D$, and $E$ must be doubly stochastic. But the guess is certainly very interesting!
Jul 30, 2020 at 21:08 history undeleted vidyarthi
Jul 30, 2020 at 21:08 history edited vidyarthi CC BY-SA 4.0
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Jul 30, 2020 at 20:33 history deleted vidyarthi via Vote
Jul 30, 2020 at 20:30 history edited vidyarthi CC BY-SA 4.0
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Jul 30, 2020 at 20:17 history answered vidyarthi CC BY-SA 4.0