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Dec 9, 2017 at 6:58 vote accept Asaf Shachar
Apr 27, 2017 at 10:29 history bounty awarded Asaf Shachar
Apr 26, 2017 at 6:53 comment added Asaf Shachar (This is discussed here).
Apr 26, 2017 at 6:53 comment added Asaf Shachar Thanks. An interesting point is that your theorem holds for any metric compatible connection. I wonder whether it is obvious that the exression $ \langle \widehat\Phi'(v(x)), \nabla_tv(x)\rangle$ is indeed independent of the connection (as long as it is metric). A similar "converse" phenomena happens for the codifferential $\delta$: If you fix a connection $\nabla$ on a bundle $E$, then for any $\nabla$-compatible metric, you get the same $\delta$ .
Apr 25, 2017 at 3:47 history edited Deane Yang CC BY-SA 3.0
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Apr 25, 2017 at 3:46 history undeleted Deane Yang
Apr 25, 2017 at 3:36 history deleted Deane Yang via Vote
Apr 25, 2017 at 3:35 history answered Deane Yang CC BY-SA 3.0