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Feb 13, 2010 at 5:44 comment added Sridhar Ramesh No, I don't think you've missed anything; at any rate, certainly not anything completely obvious. I'd answer your Question 1 (now, wiser than I started...) with "Yes".
Feb 13, 2010 at 5:41 history edited Sridhar Ramesh CC BY-SA 2.5
added 130 characters in body
Feb 10, 2010 at 20:48 comment added Andrew Stacey Thanks for the clarifications. I wondered if there was some issue with finite/infinite stuff that I was completely unaware of. I feel reassured that at least I didn't miss something completely obvious - should I be feeling that? Or is there still something I've missed in my setup?
Feb 10, 2010 at 19:51 comment added Sridhar Ramesh Such morphisms will automatically satisfy the appropriate commutative diagrams (by virtue of the appropriate equations holding in each algebra Hom(c^k, c)). Thus, they can be combined into what I thought of as an M object. I haven't sat down and checked all the details, but I am quite confident now that it works and I was wrong.)
Feb 10, 2010 at 19:50 comment added Sridhar Ramesh (Why? The latter amounts to just putting the structure of a Set-algebra for M on Hom(x, c) for each x, such that precomposition is a homomorphism of such algebras. For every element in M(k), thought of as a k-ary operation, we obtain a morphism from c^k to c by applying that operation to the k many projections in Hom(c^k, c), from which the result of that operation on arbitrary Hom(x, c) is determined... [continued in next comment]
Feb 10, 2010 at 19:31 comment added Sridhar Ramesh Egads, no, you're right. The correspondence does go both ways. I failed to see it before, being so used to viewing things one way, but if M is a monad on Set, then product-preserving functors from the dual of M's Kleisli category to C (what I was thinking of as an M object) are in correspondence with tuples of the form <contravariant functor F from C to the category of Set-algebras of M, object c in C such that the product of any set of copies of c exists, and natural isomorphism between Hom_C(-, c) and UnderlyingSet(F(-))> (what you were thinking of as an M object). So, I retract my "No".
Feb 10, 2010 at 11:43 comment added Andrew Stacey But it all works if I replace "compact Hausdorff" by "group", doesn't it? Maybe I'm missing something there as well. If so, perhaps I should ask the more basic question about the difference between finitary and infinitary theories first.
Feb 10, 2010 at 10:57 history undeleted Sridhar Ramesh
Feb 10, 2010 at 10:57 history edited Sridhar Ramesh CC BY-SA 2.5
Minor rewording
Feb 10, 2010 at 10:47 history deleted Sridhar Ramesh
Feb 10, 2010 at 10:42 history edited Sridhar Ramesh CC BY-SA 2.5
Hesitation, considering deletion
Feb 10, 2010 at 10:41 history undeleted Sridhar Ramesh
Feb 10, 2010 at 10:40 history deleted Sridhar Ramesh
Feb 10, 2010 at 10:35 history answered Sridhar Ramesh CC BY-SA 2.5