Welcome to Subscribe On Youtube
1910. Remove All Occurrences of a Substring
Description
Given two strings s and part, perform the following operation on s until all occurrences of the substring part are removed:
- Find the leftmost occurrence of the substring
partand remove it froms.
Return s after removing all occurrences of part.
A substring is a contiguous sequence of characters in a string.
Example 1:
Input: s = "daabcbaabcbc", part = "abc" Output: "dab" Explanation: The following operations are done: - s = "daabcbaabcbc", remove "abc" starting at index 2, so s = "dabaabcbc". - s = "dabaabcbc", remove "abc" starting at index 4, so s = "dababc". - s = "dababc", remove "abc" starting at index 3, so s = "dab". Now s has no occurrences of "abc".
Example 2:
Input: s = "axxxxyyyyb", part = "xy" Output: "ab" Explanation: The following operations are done: - s = "axxxxyyyyb", remove "xy" starting at index 4 so s = "axxxyyyb". - s = "axxxyyyb", remove "xy" starting at index 3 so s = "axxyyb". - s = "axxyyb", remove "xy" starting at index 2 so s = "axyb". - s = "axyb", remove "xy" starting at index 1 so s = "ab". Now s has no occurrences of "xy".
Constraints:
1 <= s.length <= 10001 <= part.length <= 1000s andpartconsists of lowercase English letters.
Solutions
-
class Solution { public String removeOccurrences(String s, String part) { while (s.contains(part)) { s = s.replaceFirst(part, ""); } return s; } } -
class Solution { public: string removeOccurrences(string s, string part) { int m = part.size(); while (s.find(part) != -1) { s = s.erase(s.find(part), m); } return s; } }; -
class Solution: def removeOccurrences(self, s: str, part: str) -> str: while part in s: s = s.replace(part, '', 1) return s -
func removeOccurrences(s string, part string) string { for strings.Contains(s, part) { s = strings.Replace(s, part, "", 1) } return s } -
function removeOccurrences(s: string, part: string): string { while (s.includes(part)) { s = s.replace(part, ''); } return s; }