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832. Flipping an Image
Description
Given an n x n binary matrix image, flip the image horizontally, then invert it, and return the resulting image.
To flip an image horizontally means that each row of the image is reversed.
- For example, flipping
[1,1,0]horizontally results in[0,1,1].
To invert an image means that each 0 is replaced by 1, and each 1 is replaced by 0.
- For example, inverting
[0,1,1]results in[1,0,0].
Example 1:
Input: image = [[1,1,0],[1,0,1],[0,0,0]] Output: [[1,0,0],[0,1,0],[1,1,1]] Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]]. Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
Example 2:
Input: image = [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]] Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]] Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]]. Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
Constraints:
n == image.lengthn == image[i].length1 <= n <= 20images[i][j]is either0or1.
Solutions
-
class Solution { public int[][] flipAndInvertImage(int[][] image) { for (var row : image) { int i = 0, j = row.length - 1; for (; i < j; ++i, --j) { if (row[i] == row[j]) { row[i] ^= 1; row[j] ^= 1; } } if (i == j) { row[i] ^= 1; } } return image; } } -
class Solution { public: vector<vector<int>> flipAndInvertImage(vector<vector<int>>& image) { for (auto& row : image) { int i = 0, j = row.size() - 1; for (; i < j; ++i, --j) { if (row[i] == row[j]) { row[i] ^= 1; row[j] ^= 1; } } if (i == j) { row[i] ^= 1; } } return image; } }; -
class Solution: def flipAndInvertImage(self, image: List[List[int]]) -> List[List[int]]: n = len(image) for row in image: i, j = 0, n - 1 while i < j: if row[i] == row[j]: row[i] ^= 1 row[j] ^= 1 i, j = i + 1, j - 1 if i == j: row[i] ^= 1 return image -
func flipAndInvertImage(image [][]int) [][]int { for _, row := range image { i, j := 0, len(row)-1 for ; i < j; i, j = i+1, j-1 { if row[i] == row[j] { row[i] ^= 1 row[j] ^= 1 } } if i == j { row[i] ^= 1 } } return image } -
/** * @param {number[][]} image * @return {number[][]} */ var flipAndInvertImage = function (image) { for (const row of image) { let i = 0; let j = row.length - 1; for (; i < j; ++i, --j) { if (row[i] == row[j]) { row[i] ^= 1; row[j] ^= 1; } } if (i == j) { row[i] ^= 1; } } return image; };