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| 1 | +// A hashmap based C++ program to clone a binary |
| 2 | +// tree with random pointers |
| 3 | +#include<iostream> |
| 4 | +#include<unordered_map> |
| 5 | +using namespace std; |
| 6 | + |
| 7 | +/* A binary tree node has data, pointer to left child, |
| 8 | +a pointer to right child and a pointer to |
| 9 | +random node*/ |
| 10 | +struct Node |
| 11 | +{ |
| 12 | +int key; |
| 13 | +struct Node* left, *right, *random; |
| 14 | +}; |
| 15 | + |
| 16 | +/* Helper function that allocates a new Node with the |
| 17 | +given data and NULL left, right and random pointers. */ |
| 18 | +Node* newNode(int key) |
| 19 | +{ |
| 20 | +Node* temp = new Node; |
| 21 | +temp->key = key; |
| 22 | +temp->random = temp->right = temp->left = NULL; |
| 23 | +return (temp); |
| 24 | +} |
| 25 | + |
| 26 | +/* Given a binary tree, print its Nodes in inorder*/ |
| 27 | +void printInorder(Node* node) |
| 28 | +{ |
| 29 | +if (node == NULL) |
| 30 | +return; |
| 31 | + |
| 32 | +/* First recur on left subtree */ |
| 33 | +printInorder(node->left); |
| 34 | + |
| 35 | +/* then print data of Node and its random */ |
| 36 | +cout << "[" << node->key << " "; |
| 37 | +if (node->random == NULL) |
| 38 | +cout << "NULL], "; |
| 39 | +else |
| 40 | +cout << node->random->key << "], "; |
| 41 | + |
| 42 | +/* now recur on right subtree */ |
| 43 | +printInorder(node->right); |
| 44 | +} |
| 45 | + |
| 46 | +/* This function creates clone by copying key |
| 47 | +and left and right pointers. This function also |
| 48 | +stores mapping from given tree node to clone. */ |
| 49 | +Node* copyLeftRightNode(Node* treeNode, unordered_map<Node *, Node *> &mymap) |
| 50 | +{ |
| 51 | +if (treeNode == NULL) |
| 52 | +return NULL; |
| 53 | +Node* cloneNode = newNode(treeNode->key); |
| 54 | +mymap[treeNode] = cloneNode; |
| 55 | +cloneNode->left = copyLeftRightNode(treeNode->left, mymap); |
| 56 | +cloneNode->right = copyLeftRightNode(treeNode->right, mymap); |
| 57 | +return cloneNode; |
| 58 | +} |
| 59 | + |
| 60 | +// This function copies random node by using the hashmap built by |
| 61 | +// copyLeftRightNode() |
| 62 | +void copyRandom(Node* treeNode, Node* cloneNode, unordered_map<Node *, Node *> &mymap) |
| 63 | +{ |
| 64 | +if (cloneNode == NULL) |
| 65 | +return; |
| 66 | +cloneNode->random = mymap[treeNode->random]; |
| 67 | +copyRandom(treeNode->left, cloneNode->left, mymap); |
| 68 | +copyRandom(treeNode->right, cloneNode->right, mymap); |
| 69 | +} |
| 70 | + |
| 71 | +// This function makes the clone of given tree. It mainly uses |
| 72 | +// copyLeftRightNode() and copyRandom() |
| 73 | +Node* cloneTree(Node* tree) |
| 74 | +{ |
| 75 | +if (tree == NULL) |
| 76 | +return NULL; |
| 77 | +unordered_map<Node *, Node *> mymap; |
| 78 | +Node* newTree = copyLeftRightNode(tree, mymap); |
| 79 | +copyRandom(tree, newTree, mymap); |
| 80 | +return newTree; |
| 81 | +} |
| 82 | + |
| 83 | +/* Driver program to test above functions*/ |
| 84 | +int main() |
| 85 | +{ |
| 86 | +//Test No 1 |
| 87 | +Node *tree = newNode(1); |
| 88 | +tree->left = newNode(2); |
| 89 | +tree->right = newNode(3); |
| 90 | +tree->left->left = newNode(4); |
| 91 | +tree->left->right = newNode(5); |
| 92 | +tree->random = tree->left->right; |
| 93 | +tree->left->left->random = tree; |
| 94 | +tree->left->right->random = tree->right; |
| 95 | + |
| 96 | +// Test No 2 |
| 97 | +// tree = NULL; |
| 98 | + |
| 99 | +// Test No 3 |
| 100 | +// tree = newNode(1); |
| 101 | + |
| 102 | +// Test No 4 |
| 103 | +/* tree = newNode(1); |
| 104 | +tree->left = newNode(2); |
| 105 | +tree->right = newNode(3); |
| 106 | +tree->random = tree->right; |
| 107 | +tree->left->random = tree; |
| 108 | +*/ |
| 109 | + |
| 110 | +cout << "Inorder traversal of original binary tree is: \n"; |
| 111 | +printInorder(tree); |
| 112 | + |
| 113 | +Node *clone = cloneTree(tree); |
| 114 | + |
| 115 | +cout << "\n\nInorder traversal of cloned binary tree is: \n"; |
| 116 | +printInorder(clone); |
| 117 | + |
| 118 | +return 0; |
| 119 | +} |
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