docs: fix bifunctor bimap Result example #646
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The original example `let resOk11 = bimap ((+) 1) string (Ok 10)` implied that the first function would be applied to the Result when it is `Ok` (returning OK 11). However, this is backwards to the actual implementation: ```fsharp let resOk11 = bimap ((+) 1) string (Ok 10) // val resOk11: Result<string,int> = Ok "10" ``` I have switched the order of the functions so that it produces the result expected (based on the name of the value binding `resOk11`): ```fsharp let resOk11 = bimap string ((+) 1) (Ok 10) // val resOk11: Result<int,string> = Ok 11 ```
wallymathieu pushed a commit that referenced this pull request Oct 28, 2025
The original example `let resOk11 = bimap ((+) 1) string (Ok 10)` implied that the first function would be applied to the Result when it is `Ok` (returning OK 11). However, this is backwards to the actual implementation: ```fsharp let resOk11 = bimap ((+) 1) string (Ok 10) // val resOk11: Result<string,int> = Ok "10" ``` I have switched the order of the functions so that it produces the result expected (based on the name of the value binding `resOk11`): ```fsharp let resOk11 = bimap string ((+) 1) (Ok 10) // val resOk11: Result<int,string> = Ok 11 ```
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The original example
let resOk11 = bimap ((+) 1) string (Ok 10)implied that the first function would be applied to the Result when it isOk(returningOk 11). However, this is backwards to the actual implementation:I have switched the order of the functions so that it produces the result expected (based on the name of the value binding
resOk11):