Concatenation of Array

Author: anantkaushik

1929-concatenation-of-array.py

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+"""
+Problem Link: https://leetcode.com/problems/concatenation-of-array/
+
+Given an integer array nums of length n, you want to create an array ans of length 2n where ans[i] == nums[i] and 
+ans[i + n] == nums[i] for 0 <= i < n (0-indexed).
+Specifically, ans is the concatenation of two nums arrays.
+Return the array ans.
+
+Example 1:
+Input: nums = [1,2,1]
+Output: [1,2,1,1,2,1]
+Explanation: The array ans is formed as follows:
+- ans = [nums[0],nums[1],nums[2],nums[0],nums[1],nums[2]]
+- ans = [1,2,1,1,2,1]
+
+Example 2:
+Input: nums = [1,3,2,1]
+Output: [1,3,2,1,1,3,2,1]
+Explanation: The array ans is formed as follows:
+- ans = [nums[0],nums[1],nums[2],nums[3],nums[0],nums[1],nums[2],nums[3]]
+- ans = [1,3,2,1,1,3,2,1]
+
+Constraints:
+n == nums.length
+1 <= n <= 1000
+1 <= nums[i] <= 1000
+"""
+class Solution:
+ def getConcatenation(self, nums: List[int]) -> List[int]:
+ l = len(nums)
+ for index in range(l):
+ nums.append(nums[index])
+ 
+ return nums