Description of the Problem

Implement int sqrt(int x).

Compute and return the square root of x, where x is guaranteed to be a non-negative integer.

Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.

Example 1:

Input: 4 Output: 2 

Example 2:

Input: 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned. 

Code

class Solution: def mySqrt(self, x: int) -> int: 

Link To The LeetCode Problem

LeetCode