|
| 1 | +#include <iostream> |
| 2 | +#include <string> |
| 3 | +#include <vector> |
| 4 | + |
| 5 | +#define END std::string("#") |
| 6 | + |
| 7 | +/** |
| 8 | + * Returns the index of a value contained in a given vector. |
| 9 | + * |
| 10 | + * @param value |
| 11 | + * char whose index is wanted. |
| 12 | + * @param list |
| 13 | + * vector of char where the value is contained. |
| 14 | + * |
| 15 | + * @returns int with the index of the value bounded in [0, n), where |
| 16 | + * n is the size of the vector. |
| 17 | + */ |
| 18 | +int getIndex(char value, std::vector<char> list){ |
| 19 | +int i; |
| 20 | +for (i = 0; i < (int)list.size(); i++){ |
| 21 | +if(value == list.at(i)) |
| 22 | +return i; |
| 23 | +} |
| 24 | + |
| 25 | +return -1; |
| 26 | +} |
| 27 | + |
| 28 | +/** |
| 29 | + * Returns true if the incoming vector letters contains the |
| 30 | + * character searched. |
| 31 | + * |
| 32 | + * @param searched |
| 33 | + * char which may be contained in the vector. |
| 34 | + * @param letters |
| 35 | + * vector of char where the character is going to be |
| 36 | + * searched. |
| 37 | + * |
| 38 | + * @returns true if searched is contained in letters. |
| 39 | + */ |
| 40 | +bool isInTheList(char searched, std::vector<char> letters){ |
| 41 | +unsigned int i; |
| 42 | + |
| 43 | +for(i = 0; i < letters.size(); i++){ |
| 44 | +if(letters.at(i) == searched) |
| 45 | +return true; |
| 46 | +} |
| 47 | + |
| 48 | +return false; |
| 49 | +} |
| 50 | + |
| 51 | +/** |
| 52 | + * Generates a vector with all the characters used in all the |
| 53 | + * words. Those characters are not repeated. |
| 54 | + * |
| 55 | + * @param words |
| 56 | + * vector of string which will be used to generate the |
| 57 | + * list of characters used. |
| 58 | + * |
| 59 | + * @returns vector of char with every character used. |
| 60 | + */ |
| 61 | +std::vector<char> lettersUsed(std::vector<std::string> words) |
| 62 | +{ |
| 63 | +std::vector<char> letters; |
| 64 | +unsigned int i, j; |
| 65 | + |
| 66 | +for(i = 0; i < words.size(); i++){ |
| 67 | +for(j = 0; j < words.at(i).size(); j++){ |
| 68 | +if(!isInTheList(words.at(i).at(j), letters)){ |
| 69 | +letters.push_back(words.at(i).at(j)); |
| 70 | +} |
| 71 | +} |
| 72 | +} |
| 73 | + |
| 74 | +return letters; |
| 75 | +} |
| 76 | + |
| 77 | +int getIndexOfRoot(bool **tree, int size){ |
| 78 | +int i, j; |
| 79 | +for(j = 0; j < size; j++){ |
| 80 | +for (i = 0; i < size; i++){ |
| 81 | +if(tree[i][j]) |
| 82 | +continue; |
| 83 | +return i; |
| 84 | +} |
| 85 | +} |
| 86 | +return -1; |
| 87 | +} |
| 88 | + |
| 89 | +bool isLastNode(bool **tree, int size, int node){ |
| 90 | +int i; |
| 91 | +for(i = 0; i < size; i++){ |
| 92 | +if(tree[node][i]) |
| 93 | +return false; |
| 94 | +} |
| 95 | +return true; |
| 96 | +} |
| 97 | + |
| 98 | +bool contains(std::vector<int> parents, int node){ |
| 99 | +int i; |
| 100 | + |
| 101 | +for(i = 0; i < (int)parents.size(); i++){ |
| 102 | +if(parents.at(i) == node) |
| 103 | +return true; |
| 104 | +} |
| 105 | +return false; |
| 106 | +} |
| 107 | + |
| 108 | +bool isTheOnlyFather(bool **tree, int size, int son, int father, |
| 109 | +std::vector<int> parents){ |
| 110 | +int i; |
| 111 | + |
| 112 | +for(i = 0; i < size; i++){ |
| 113 | +//if this father is not the given father |
| 114 | +//and |
| 115 | +//this father is not in the list |
| 116 | +//return false |
| 117 | +if(tree[i][son] && i != father && !contains(parents, i)){ |
| 118 | +return false; |
| 119 | +} |
| 120 | +} |
| 121 | +return true; |
| 122 | +} |
| 123 | + |
| 124 | +void sortTree(bool **tree, int size, std::vector<char> letters) |
| 125 | +{ |
| 126 | +/*Rules: |
| 127 | + * + Each node must be (1,1) at the end, except |
| 128 | + * for node n0 which must be (0,1) and node nN, which |
| 129 | + * must be (1,0) |
| 130 | + * + Once a node is read, it's added to the list of |
| 131 | + * read elements R |
| 132 | + * |
| 133 | + * Process: |
| 134 | + * + Searches n0 by searching for a (0,1) node. |
| 135 | + * + nX = n0 |
| 136 | + * + Loop: |
| 137 | + * + Searches for a son node nX+1 of nX |
| 138 | + * whose only father out of R is nX |
| 139 | + * + Stores nX in R |
| 140 | + * + If(nX+1 didn't appear) |
| 141 | + * + Congrats! It is nN |
| 142 | + * + End of the sorting |
| 143 | + * + nX+1 now is nX |
| 144 | + * + R contains the list |
| 145 | + */ |
| 146 | +int i; |
| 147 | +int sonNode = -1; |
| 148 | +int fatherNode = getIndexOfRoot(tree, size); |
| 149 | +std::vector<int> r; |
| 150 | + |
| 151 | +do { |
| 152 | +for(i = 0; i < size; i++){ |
| 153 | +if(tree[fatherNode][i] && isTheOnlyFather(tree, size, i, |
| 154 | +fatherNode, r)) |
| 155 | +sonNode = i; |
| 156 | +} |
| 157 | +r.push_back(fatherNode); |
| 158 | +fatherNode = sonNode; |
| 159 | +} while(!isLastNode(tree, size, sonNode)); |
| 160 | +r.push_back(fatherNode); |
| 161 | + |
| 162 | +for(i = 0; i < size; i++){ |
| 163 | +std::cout << letters.at(r.at(i)); |
| 164 | +} |
| 165 | +std::cout << '\n'; |
| 166 | +} |
| 167 | + |
| 168 | + |
| 169 | +void fillBoolTree(bool **tree, int size, std::vector<std::string> words, |
| 170 | +std::vector<char> letters) |
| 171 | +{ |
| 172 | +/* |
| 173 | + * 1: write down links between nodes |
| 174 | + * 2: search groups of words with the same initial char |
| 175 | + * 2.1: char to temp; boolean repeated = false |
| 176 | + * 2.2: if next char is the same, temp to list L and |
| 177 | + * repeated = true |
| 178 | + * 2.3: when next char is different, repeat from 2.1 |
| 179 | + * 2.4: when list is finished, take chars from L |
| 180 | + * 2.4.1: takes char C |
| 181 | + * 2.4.2: looks and inserts every word which begins |
| 182 | + * with C in list tempList |
| 183 | + * 2.4.3: removes the first char of every word |
| 184 | + * 2.4.4: sends tempList to fillBoolTree |
| 185 | + */ |
| 186 | +unsigned int i, j, indexA, indexB; |
| 187 | +char tempChar = '\0'; |
| 188 | +std::vector<char> groups; |
| 189 | +std::vector<std::string> tempList; |
| 190 | +bool repeated = false; |
| 191 | + |
| 192 | +// Writes down the connections between nodes |
| 193 | +for(i = 1; i < words.size(); i++){ |
| 194 | +indexA = getIndex(words.at(i-1).at(0), letters); |
| 195 | +indexB = getIndex(words.at(i).at(0), letters); |
| 196 | +if(indexA != indexB) |
| 197 | +tree[indexA][indexB] = true; |
| 198 | +} |
| 199 | + |
| 200 | +// Checks for groups of words and writes down the initial characters |
| 201 | +for(i = 0; i < words.size(); i++){ |
| 202 | +if(words.at(i).at(0) != tempChar){ |
| 203 | +tempChar = words.at(i).at(0); |
| 204 | +repeated = false; |
| 205 | +} else if(words.at(i).at(0) == tempChar && repeated == false){ |
| 206 | +groups.push_back(tempChar); |
| 207 | +repeated = true; |
| 208 | +} |
| 209 | +} |
| 210 | + |
| 211 | +// For every character that sets every group, generates a list and |
| 212 | +// calls fillBoolTree without the first character |
| 213 | +for(i = 0; i < groups.size(); i++){ |
| 214 | +for(j = 0; j < words.size(); j++){ |
| 215 | +if(groups.at(i) == words.at(j).at(0) && |
| 216 | +words.at(j).substr(1) != ""){ |
| 217 | +tempList.push_back(words.at(j)); |
| 218 | +tempList.at(tempList.size()-1). |
| 219 | +erase(tempList.at(tempList.size()-1).begin()); |
| 220 | +} |
| 221 | +} |
| 222 | + |
| 223 | +fillBoolTree(tree, size, tempList, letters); |
| 224 | +tempList.clear(); |
| 225 | +} |
| 226 | + |
| 227 | +} |
| 228 | + |
| 229 | +int main(void) |
| 230 | +{ |
| 231 | +std::vector<std::string> words; |
| 232 | +std::string temp; |
| 233 | +unsigned int size, i, j; |
| 234 | + |
| 235 | +while (std::cin >> temp && temp != END) |
| 236 | +{ |
| 237 | +words.push_back(temp); |
| 238 | +} |
| 239 | + |
| 240 | +std::vector<char> letters(lettersUsed(words)); |
| 241 | +size = letters.size(); |
| 242 | + |
| 243 | +bool **tree = new bool*[size]; |
| 244 | +for(i = 0; i < size; i++) // How to find array size |
| 245 | +{ |
| 246 | +tree[i] = new bool[size]; |
| 247 | +for(j = 0; j < size; j++) |
| 248 | +{ |
| 249 | +tree[i][j] = false; |
| 250 | +} |
| 251 | +} |
| 252 | + |
| 253 | +fillBoolTree(tree, size, words, letters); |
| 254 | + |
| 255 | +sortTree(tree, size, letters); |
| 256 | + |
| 257 | +return 0; |
| 258 | +} |
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