Translated "lab301019"

programming_lab/lab301019/count_elements_list.py

@@ -0,0 +1,78 @@
+#!/usr/bin/env python3
+# -*- coding: utf-8 -*-
+"""
+Created on Wed Oct 30 09:52:14 2019
+
+@author: angelo
+Write a function that takes a list and returns a new list made up of tuples. 
+Each element of the tuple has the first element which is an element of the input list and the second which is the number of times the element repeats starting from that position. 
+The same elements must be in the same order as the input list.
+
+ex: [1,2,2,2,"b","a","a",2.0,2.0,2.0,"home","home",2.0]
+returns
+[(1,1),(2,3),("b",1),("a",2),(2.0,4),("home",2)]
+"""
+
+
+def count_elements_list(list):
+ dic = {}
+ for element in list:
+ dic[element] = list.count(element)
+ return list(dic.items())
+
+
+def count_elements_list2(list):
+ dic = {}
+ for element in list:
+ if element not in dic:
+ dic[element] = list.count(element)
+ return list(dic.items())
+
+
+def count_elements_list3(list):
+ dic = {}
+ for element in list:
+ if element not in dic:
+ dic[element] = 1
+ else:
+ dic[element] += 1
+ return list(dic.items())
+
+
+def count_elements_list4(list):
+ dic = {}
+ for element in list:
+ t = element, type(element)
+ if t not in dic:
+ dic[t] = 1
+ else:
+ dic[t] += 1
+ list_ret = []
+ for tuple, repetitions in dic.items():
+ list_ret.append((tuple[0], repetitions))
+ return list_ret
+
+
+def count_elements_list5(list):
+ dic = {(element, type(element)): 0 for element in list}
+ for element in list:
+ t = element, type(element)
+ dic[t] += 1
+ return [(tuple[0], dic[tuple]) for tuple in dic]
+
+
+def count_elements_list6(list):
+ dic = {}
+ for element in list:
+ try:
+ dic[element] += 1
+ except:
+ dic[element] = 1
+ return list(dic.items())
+
+
+def count_elements_list7(list):
+ dic = {}
+ for element in list:
+ dic[element] = dic.get(element, 0) + 1
+ return list(dic.items())

programming_lab/lab301019/file_10.py

@@ -4,30 +4,30 @@
 Created on Wed Oct 30 16:25:54 2019
 
 @author: angelo
-Scriviamo una funzione che prende come parametro il nome di un file e ci stampa dentro tutti i numeri da 0 a 9 su righe diverse. Ritorna 0.
+We write a function that takes the name of a file as a parameter and prints all the numbers from 0 to 9 on different lines. Returns 0.
 """
 
 
-def file_10(nomefile):
- f = open(nomefile, "w")
- stringa = ""
+def file_10(filename):
+ f = open(filename, "w")
+ string = ""
  for i in range(10):
- stringa += str(i) + "\n"
- f.write(stringa)
+ string += str(i) + "\n"
+ f.write(string)
  f.close()
  return 0
 
 
-def file_102(nomefile):
- f = open(nomefile, "w")
+def file_102(filename):
+ f = open(filename, "w")
  for i in range(10):
  f.write(str(i) + "\n")
  f.close()
  return 0
 
 
-def file_103(nomefile):
- with open(nomefile, "w") as f:
- lista = [str(i) + "\n" for i in range(10)]
- f.writelines(lista)
+def file_103(filename):
+ with open(filename, "w") as f:
+ list = [str(i) + "\n" for i in range(10)]
+ f.writelines(list)
  return 0

programming_lab/lab301019/find_vowel.py

@@ -0,0 +1,31 @@
+#!/usr/bin/env python3
+# -*- coding: utf-8 -*-
+"""
+Created on Wed Oct 30 12:44:03 2019
+
+@author: angelo
+Write a function that takes a file name and returns the vowel that repeats the most times on the same line in the file. If there are vowels that are repeated the same number of times, the first one found returns.
+
+ex:
+ rotto
+ topo
+ missili
+
+ returns i
+"""
+
+
+def find_vowel(filename):
+ with open(filename) as f:
+ maxvow = 0
+ voc = ""
+ for line in f:
+ for vowel in "aeiou":
+ cont = line.count(vowel)
+ if cont > maxvoc:
+ voc = vowel
+ maxvoc = cont
+ return voc
+
+
+find_vowel("head_vowels.txt")

programming_lab/lab301019/foo.txt

@@ -0,0 +1 @@
+Hi how are you?

programming_lab/lab301019/head_vocals.txt

@@ -0,0 +1,7 @@
+aaaaaaaaaaaaa
+top
+broken
+missile
+horror
+sticky
+cicciociccio

programming_lab/lab301019/vocale_massima.py → programming_lab/lab301019/maximum_vowel.py

@@ -4,21 +4,21 @@
 Created on Wed Oct 30 17:49:25 2019
 
 @author: angelo
-Scrivere una funzione che prende una stringa che è il nome di un file, e ritorna la vocale che è presente più volte su una stessa riga del file
+Write a function that takes a string that is the name of a file, and returns the vowel that occurs multiple times on the same line of the file
 
-Es: se il file contiene
+Ex: if the file contains
  buffo
- papa
+ pope
  richiami
 
- ritorna 'i'
+ return 'i'
 """
 
 
-def vocale_massima(nomefile):
+def maximum_vowel(filename):
  ripvoc = 0
  voc = ""
- with open(nomefile) as f:
+ with open(filename) as f:
  for line in f:
  for v in "aeiou":
  cont = line.count(v)