class Solution { public: int minInsertions(string s) { int n = s.length(); vector<int> dp(n); for (int i = n - 2; i >= 0; i--) { int prev = 0; for (int j = i + 1; j < n; j++) { int temp = dp[j]; if (s[i] == s[j]) { dp[j] = prev; } else { dp[j] = min(dp[j], dp[j-1]) + 1; } prev = temp; } } return dp[n-1]; } };
leetcode
challenge
Here is the link for the problem:
https://leetcode.com/problems/minimum-insertion-steps-to-make-a-string-palindrome/
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