How to omit enum name in variant

In my Rust journey I still discover some less known gems. Today's hero is use. In most programming languages it is responsible both for reaching to some code and bringing it into the scope. In Rust this functionality is divided between mod and use - mod makes something visible, use shortens the call by creating local bindings.

That brings us to enums. A lot of my code looked like this:

enum SomeLongAndDescriptiveName { Foo, Bar } fn main() { let a = SomeLongAndDescriptiveName::Foo; match a { SomeLongAndDescriptiveName::Foo => (), SomeLongAndDescriptiveName::Bar => (), } } 

In order to shorten it use can be used to locally bind enum members:

enum SomeLongAndDescriptiveName { Foo, Bar } use SomeLongAndDescriptiveName::*; fn main() { let a = Foo; match a { Foo => (), Bar => (), } } 

That instantaneously made my code much more readable. Especially when using alternatives Foo|Bar syntax in match or joined if let statements from Rust 1.88.

Note 1: When using enum from some other module if you need both enum type and enum variants it looks like this:

mod other; use other::SomeLongAndDescriptiveName::{self, *}; fn flip ( x: SomeLongAndDescriptiveName ) -> SomeLongAndDescriptiveName { // enum type match x { Foo => Bar, // enum variant Bar => Foo } } 

Note 2: You can rename everything if needed, including variants:

mod other; use other::SomeLongAndDescriptiveName::{self as E, Foo as F, Bar as B}; fn flip ( x: E ) -> E { match x { F => B, B => F } } 

So if you come to Rust from some other language with "classic" use semantic don't be afraid to use use more frequently for convenience/readability binding.