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JavaScript Implementation of FizzBuzz in functional programming

The FizzBuzz problem is a classic test given in coding interviews. The task is simple: Print integers 1 to N, but print “Fizz” if an integer is divisible by 3, “Buzz” if an integer is divisible by 5, and “FizzBuzz” if an integer is divisible by both 3 and 5.

const isFizz = number => number%3 ==0; const isBuzz = number => number%5 ==0; const range = (start, end) => [...new Array(end - start).keys()].map((n) => n + start); const doFizzBuzz = (start, end) => range(start, end).map((number => { if(isFizz(number) && isBuzz(number)) { return 'FizzBuzz'; } else if(isFizz(number)) { return 'Fizz'; } else if(isBuzz(number)) { return 'Buzz'; } else { return number; } })) .join(`\n`); console.log(doFizzBuzz(1, 101)); 
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jsfiddle

https://jsfiddle.net/381g4fct/7/

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